Hello again!
It looks like you need a lot of help today. I'm glad I am able to help you!
h(x) = x³ - 2x² - 3x
The question you need to ask yourself is "How do you find the zeros of a function.
Answer: To find the zeros of a function, just set the function equal to zero then solve for x
x³ - 2x² - 3x = 0
Factor the left sides
x(x + 1)(x - 3) = 0
Now we can set factors equal to 0
x = 0 or x + 1 = 0 or x - 3 = 0
x = 0 or x = 0 - 1 or x = 0 + 3
x = 0 or x = -1 or x = 3
Thus,
The zeros of the function are: x = 0 or x = -1 or x = 3
As always, I am glad to help students like you!
Answer:
57
Step-by-step explanation:
5 |-2^3 - 2| + 7
-2^3 = -8
-8 - 2 = -10
absolute value of -10 = 10
5 * 10 = 50
50 + 7 = 57
I think the answer is (b) compress as in others , the position is changed not the shape
-9/3 + 4
-3 + 4 = 1
The answer to the question
i think the answer is c :)
