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3 years ago

Write a word problem that includes substitution and elimination and solve it.

2 answers:

5 0

Hello there,

The following would be an example will be an example of a word problem that includes substitution and elimination and solve it.

Billy-bob want's to buy some cookies. His kid's named "texaschica" and "Astute" and "Buckethead" want some cookies. "texaschica" wanted 2. "astute" wanted 5. And "buckethead" wanted 12. So how many cookies does billy-bob have to buy?

2x+5x+12x.

So the first thing we want to do is eliminate and take off the x's.

No let's do the problem.

2+5+12= 19.

We can now substitute the x's

Your correct answer would be 19x.

Hope this helps.

~Jurgen

zheka24 [161]3 years ago

4 0

Elimination :

u went to the store and purchases 2 shirts and 3 caps and spend 20 bucks. ur friend went to the same store and purchased 3 shirts and 1 cap and spend 16 bucks. What was the price of a shirt and a cap ? (x = shirts and y = caps)

2x + 3y = 20
3x + y = 16....multiply by -3
---------------
2x + 3y = 20
-9x - 3y = - 48 (result of multiplying by -3)
---------------add
-7x = - 28
x = -28/-7
x = 4 <=== each shirt costs $ 4

3x + y = 16
3(4) + y = 16
12 + y = 16
y = 16 - 12
y = 4 <=== each cap costs $ 4
=======================
substitution :
Mike is 5 years older then 4 times his daughters age. His daughter is 7 years old. How old is Mike ? (x = daughters age)

m = 4x + 5
x = 7

m = 4(7) + 5
m = 28 + 5
m = 33 <=== Mike's age

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What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?

astraxan [27]

ANSWER

The value of the expression is
$- 1$

EXPLANATION

Method 1: Rewrite as product of
${i}^{2}$

The expression given to us is,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4}$

We use the fact that
${i}^{2} = - 1$
to simplify the above expression.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{1} \times {i}^{3} \times {i}^{2} \times {i}^{4}$

This implies,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2}$

We substitute to obtain,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times - 1 \times - 1 \times - 1\times - 1 \times - 1$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times 1 \times 1 \times - 1 = - 1$

Method 2: Use indices to solve.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0 + 1 + 2 + 3 + 4}$

This implies that,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{10}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( {{i}^{2}} )^{5}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( - 1 )^{5} = - 1$

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Function A is linear

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3 years ago

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A college surveys 300 graduates and finds 98 graduated with honors and 207 had one or both parents graduate from college. Of the

musickatia [10]

Answer:

20.43% probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Graduated with honors:

98 students graduated with honors. Of those, 79 had at least one parent graduating from college. So 98 - 79 = 19 did not.

Of 300 students, 207 had one or both parents graduate from college. So 300 - 207 = 93 did not have at least one parent graduating.

Find the probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.

Of the 93 with no graduated parent, 19 earned honors

19/93 = 0.2043

20.43% probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.

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