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3 years ago

2. Calculate the energy in joules of a photon whose frequency is 7.55×1014 Hz.

1 answer:

8 0

The energy of a photon is given by
E = h × v

where:
E is the energy in joules/photon
'h' is the constant 6.63 × 10⁻³⁴
'v' is the frequency 7.55 × 10¹⁴

Substitute 'h' and 'v' into the formula we have

E = (6.63×10⁻³⁴) × (7.55×10¹⁴)
E = (6.63×7.55) × (10⁻³⁴ × 10¹⁴)
E = 50.0565 × 10⁽⁻³⁴⁺¹⁴⁾
E = 50 × 10⁻²⁰ joules/photon

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Complete Question:

The deck that Amos is building is in the shape of a parallelogram, DGRY. The measure of D is five-halves the measure of Y. Find the measure of each angle of the deck.

Answer:

$\angle G = \angle Y = 51.43 ^{\circ}$

$\angle D = \angle R = 128.57 ^{\circ}$

Step-by-step explanation:

Given

Shape: Parallelogram DGRY

Dimension: $\angle D = \frac{5}{2}\angle Y$

Required

Find the measure of each angle

D and R are opposite sides & G and Y are also opposite sides.

So, we have:

$\angle D = \angle R = \frac{5}{2}\angle Y$

and

$\angle G = \angle Y$

The sum of angles is given as:

$\angle D + \angle G + \angle R + \angle Y=360^{\circ}$

Substitute values for $\angle D, \angle G \ \& \angle R$

$\frac{5}{2}\angle Y + \frac{5}{2}\angle Y + \angle Y + \angle Y = 360^{\circ}$

Take LCM

$\frac{5\angle Y + 5\angle Y + 2\angle Y+ 2\angle Y}{2}= 360^{\circ}$

$\frac{14\angle Y}{2}= 360^{\circ}$

Multiply both sides by $\frac{2}{14}$

$\frac{2}{14} * \frac{14\angle Y}{2}= 360^{\circ} * \frac{2}{14}$

$\angle Y= 360^{\circ} * \frac{2}{14}$

$\angle Y= \frac{ 360^{\circ} *2}{14}$

$\angle Y= \frac{720^{\circ}}{14}$

$\angle Y= 51.43 ^{\circ}$

So:

$\angle G = \angle Y = 51.43 ^{\circ}$

$\angle D = \frac{5}{2}\angle Y$

$\angle D = \frac{5}{2} * 51.43^{\circ}$

$\angle D = \frac{5* 51.43^{\circ}}{2}$

$\angle D = \frac{257.15^{\circ}}{2}$

$\angle D = 128.57 ^{\circ}$

Hence:

$\angle D = \angle R = 128.57 ^{\circ}$

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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