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3 years ago

Express 15x^1/3 y^1/5 using a radical

Mathematics

1 answer:

worty [1.4K]3 years ago

7 0

Okay.
15 (3)radical x times (5)radical y

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If the cone and the square pyramid have the same volume, find the radius of the cross section of the cone. Round your answer to

nikdorinn [45]

Answer: R= 4.91

Pi r^2= 8^2

Pi r^2= 8.7^2

Pi r^2= 75.69

r^2=24.09

R= 4.91

6 0

3 years ago

A professor thinks that the students in her statistics class this term are less creative than most students at this university.

choli [55]

Answer:

It is not enough evidence to reject null hypothesis. It is not enough evidence to say that mean score is not equal to 35.

Step-by-step explanation:

$\mu=35\\n=23\\\=x=33\\s=5\\\alpha=0.1$

1. Null and alternative hypothesis

$H_{0}:\mu=35\\H_{1}:\mu$

2. Significance level

$\alpha=0.1\\1-\alpha=0.99$

Freedom degrees is given by:

$v=n-1\\v=23-1=22$

For a sgnificance level of 0,01 and 22 freedom degrees, t-student distribution value is:

$t_{0.01;23}=-2. 5083$

3. Test statistic

$t=\frac{\=x-\mu}{\frac{s}{\sqrt{n} } }$

$t=\frac{33-35}{\frac{5}{\sqrt{23} } }$

$t=-1,918$

In this case, we have an one left tailed analysis, it means that null hypothesis is rejected if $t$

$-1.918>-2.5083$

Conclusion:

It is not enough evidence to reject null hypothesis. It is not enough evidence to say that mean score is not equal to 35.

3 0

3 years ago

What is the volume of a rectangular prism with the base area of 15m2 and height of 5cm?

koban [17]

Answer:

The correct answer is option C. 75 m³

Step-by-step explanation:

<u>Points to remember</u>

Volume of rectangular prism = Base area * Height

<u>To find the volume of given prism</u>

Here Base area = 15 m² and

Height = 5 m

Volume = base area * height

= 15 * 5

= 75 m³

Volume of prism = 75 m³

Therefore the correct answer is option C. 75 m³

3 0

3 years ago

Read 2 more answers

If a insect is 0.095 long how long is it if looking through a microscope 100 times how long would the insect be

Sliva [168]

9.5.....................

5 0

3 years ago

A food processor packages orange juice in small jars. The weights of the filled jars are approximately normally distributed with

vovikov84 [41]

Answer:

6.68 %.

Step-by-step explanation:

The standardised z-score = ( 10.95 - 10.5) / 0.3

= 1.5.

Looking up the Normal Distribution tables ( area to the left) 1.5 corresponds to 0.93319 so for a weight above 10.95 the proportion is

1 - 0.93319 = 0.06681

= 6.68%.

4 0

2 years ago