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BigorU [14]
2 years ago
11

62 is 112% of what number? find the base and round to the nearest hundredth

Mathematics
2 answers:
Sonja [21]2 years ago
4 0
1.12x=62 , 62/1.12 = x, x = 55.36
vazorg [7]2 years ago
3 0

Answer: Hello there!

if 62 is the 112% of some number, this means that if the number is x; then the 100% of this number is x, and the 112% of this number is x + 0.12*x = 1.12*x

then this means that 62 = 1.12x

now we want to find the number x:

62 = 1.12x

x= 62/1.12 = 55.35714

now we need to round it to the nearest hundredth:

the hundredth place is the second number after the decimal point, in this case, is a 5, and we want to round it; if the next number is 5 or bigger, we round up, if it is less than 5, we round down.

We can see that the next number is a 7, so we should round up; then our number x is: 55.36

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Kyla has the number of cherries that Denise has. If Kyla has 46 cherries, how many cherries do they have altogether?​
pogonyaev

Answer:

92

Step-by-step explanation:

46 + 46 = 92

5 0
1 year ago
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What is 1 +1 pls HELP
ElenaW [278]

Answer:

2

Step-by-step explanation:

Subject: Re: Need the math proof for 1 + 1 = 2

The proof starts from the Peano Postulates, which define the natural

numbers N. N is the smallest set satisfying these postulates:

P1. 1 is in N.

P2. If x is in N, then its "successor" x' is in N.

P3. There is no x such that x' = 1.

P4. If x isn't 1, then there is a y in N such that y' = x.

P5. If S is a subset of N, 1 is in S, and the implication

(x in S => x' in S) holds, then S = N.

Then you have to define addition recursively:

Def: Let a and b be in N. If b = 1, then define a + b = a'

(using P1 and P2). If b isn't 1, then let c' = b, with c in N

(using P4), and define a + b = (a + c)'.

Then you have to define 2:

Def: 2 = 1'

2 is in N by P1, P2, and the definition of 2.

Theorem: 1 + 1 = 2

Proof: Use the first part of the definition of + with a = b = 1.

Then 1 + 1 = 1' = 2 Q.E.D.

Note: There is an alternate formulation of the Peano Postulates which

replaces 1 with 0 in P1, P3, P4, and P5. Then you have to change the

definition of addition to this:

Def: Let a and b be in N. If b = 0, then define a + b = a.

If b isn't 0, then let c' = b, with c in N, and define

a + b = (a + c)'.

You also have to define 1 = 0', and 2 = 1'. Then the proof of the

Theorem above is a little different:

Proof: Use the second part of the definition of + first:

1 + 1 = (1 + 0)'

Now use the first part of the definition of + on the sum in

parentheses: 1 + 1 = (1)' = 1' = 2 Q.E.D.

3 0
3 years ago
What is the smallest positive degree angle measure equivalent to sin^-1 (0.391)?
natta225 [31]

Given:

The value is:

\sin^{-1}(0.391)

To find:

The smallest positive degree angle measure equivalent to \sin^{-1}(0.391).

Solution:

We have,

\sin^{-1}(0.391)

Using the scientific calculator, we get

\sin^{-1}(0.391)=23.0167366398^\circ

\sin^{-1}(0.391)\approx 23^\circ

Therefore, the smallest positive degree angle measure equivalent to \sin^{-1}(0.391) is 23 degrees.

5 0
2 years ago
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Rearrange y =1/2x+1to make x the subject.
ella [17]

❤❤❤❤❤❤❤❤❤❤❤❤❤❤

y =  \frac{1}{2} x + 1 \\

Multiply sides by 2

2 \times y = 2 \times ( \frac{1}{2} x + 1) \\

2y =( 2 \times  \frac{1}{2} x) + (2 \times 1) \\

2y = x + 2

x + 2 = 2y

Subtract sides 2

x + 2 - 2 = 2y - 2

x = 2y - 2

Done...

❤❤❤❤❤❤❤❤❤❤❤❤❤

3 0
2 years ago
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