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3 years ago

Graph plz step by step

Mathematics

1 answer:

Mazyrski [523]3 years ago

5 0

Answer:

Step-by-step explanation:

The equation shown in the question can be seen graphed in the image attached below. As you can see with the graphed equation the variable x can be any real number except for -1. This is because a -1 would cause the denominator of the fraction to be equal to 0, and a fraction with a denominator as 0 is a null value and does not exist.

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Parcc chapter 7 pythagorean theorem

Bumek [7]

So, we know that a^2 + b^2 = c^2. Right? That is called the Pythagorean Theorem.

In this case. We can say that 39 is a, 40 is b, and x is c.
NOTE: It doesn't really matter whether 39 is a or b. a & b are just the two legs of the right triangle.

So, if we say that 39 is a, 40 is b, and x is c. We can plug it into the Pythagorean Theorem.

39^2 + 40^2 = x^2

I'll let you take it from there.

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3 years ago

Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.

galina1969 [7]

Answer:

All potential roots are 3,3 and $-\frac{5}{3}$ .

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

$f(x)=3x^3-13x^2-3x+45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

$p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45$

$q=\pm 1,\pm 3$

All possible roots

$\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}$

Now we check each rational root and see which are possible roots for given function.

$f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0$

$f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32$

$f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144$

$f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}$

Similarly, we will check for all value of p/q and we get

$f(-5/3)=0$

Thus, All potential roots are 3,3 and $-\frac{5}{3}$ .

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3 years ago

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Which best describes the transformation that occurs from the graph of f(x)=x^2 to g(x)=(x-2)^2+3??

Leokris [45]

answer right 2, up 3

any function with the following form is a transformation from f(x) = x²

g(x) = (x – a)² + b

were a moves the function to the right when a is a positive number and to the left when its a negative number, and b moves the function up when b is positive and down when its negative.

then for a=2 positive and b=3 positive, we have

right 2, up 3

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barxatty [35]

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