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ziro4ka [17]
3 years ago
13

Can someone help on this one because i don’t know if i’m correct

Mathematics
1 answer:
34kurt3 years ago
6 0

Answer:

Yes its C

Step-by-step explanation:

First off the y intercepts + 3 and the line hits it  not -3 so option D is out

Also the slope is negative so Option A and B are out

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For every 1 litre of water used to make a medicine, 269ml of sucrose and 47ml of saline solution are used. Express the amount of
leonid [27]

Answer:

1000 : 269 : 47

Step-by-step explanation:

A ratio is a way of comparing the value or amount of one quantity to another.

We are to find the ration of water to sucrose to saline solution, hence, it must remain in that order.

Water : Sucrose : Saline solution

The amount of water is 1 litre (1 * 1000 ml = 1000 ml)

The amount of sucrose is 269 ml

The amount of saline solution is 47 ml

Therefore, the ratio of water to sucrose to saline solution is:

W : S : SS = 1000 : 269 : 47

Since 1000, 269 and 47 have no common factors, that is the simplest form of the ratio.

3 0
3 years ago
Using a property of operations, what can you say about the sums of (-13.2) 8.1 and 13.2 (-8.1)
artcher [175]
No matter where the negative sign is, the product will always be negative, so is the number itself.

13.2(-8.1)=-106.92

twice of that would be -213.84.

first do the multiplying, then the adding(the adding of negative numbers, so it would be basically subtracting).
7 0
3 years ago
One pound of swordfish costs as much as 1.5 pounds of salmon. Mrs. O pays $39 for 2 pounds of salmon and 3 pounds of swordfish.
Dimas [21]

Answer:

The ratio of the amount for swordfish to the amount of salmon is 6:4

Step-by-step explanation:

Given as :

The price for 1 pound of swordfish = The price of 1.5 pound of salmon

So, On this relation

The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 )  pound of salmon

i.e The price for 2 pound of swordfish = The price of 3 pound of salmon

Now According to question

Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39

Let the money she pay for swordfish = 2 sw

And The money she pay for salmon = 3 sa

∵, The total money she pay for both  = $ 39

I.e  2 sw + 3 sa = 39

As 2 sw = 3 sa

So, 3 sa + 3 sa = 39

Or, 6 sa = 39

or, sa = \frac{39}{6} = \frac{13}{2}

∴ sw = \frac{13}{2} × \frac{3}{2}

or, sw = \frac{39}{4}

Now, the ratio of the amount for swordfish to the amount of salmon = \frac{\frac{39}{4}}{\frac{13}{2}}

I.e The ratio = \frac{6}{4}

Hence The ratio of the amount for swordfish to the amount of salmon is 6:4

Answer

3 0
3 years ago
Danny had 20 minutes to do a three-problem quiz. He spent 9 1/4 minutes on question A and 5 4/5 minutes on question B. How much
Travka [436]

Answer:

4 19/20

Step-by-step explanation:

9 1/4 + 5 4/5 = 15 1/20

20- 15 1/20 = 4  19/20

6 0
3 years ago
Angie baked 100 cookies and 20 brownies. She wants to  split them into equal groups  for the big sale. Each group must have the
Tresset [83]
Stop copying the question, it's confusing

so 100 cookies and 20 brownies
what is the greatest number you can divide them both by?

find the GCF
factor them
100=2*2*5*5
20=2*2*5
so the GCF is the common group to both or 2*2*5 or 20

100/20=5
20/20=1

there are 20 groups, each wit 5 cookies and 1 brownie


20 groups
7 0
3 years ago
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