To convert to a decimal, divide by 100.
75 / 100 = .75
Answer:
<em>p = ± q / 5r + 8; Option D</em>
Step-by-step explanation:
We are given the following equation; q^2 / p^2 - 16p + 64 = 25r^2;
q^2 / p^2 - 16p + 64 = 25r^2 ⇒ Let us factor p^2 - 16p + 64, as such,
p^2 - 16p + 64,
( p )^2 - 2 * ( p ) * ( 8 ) + ( 8 )^2,
( p - 8 )^2 ⇒ Now let us substitute this into the equation q^2 / p^2 - 16p + 64 = 25r^2 in replacement of p^2 - 16p + 64,
q^2 / ( p - 8 )^2 = 25r^2 ⇒ multiply either side by ( p - 8 )^2,
q^2 = 25r^2 * ( ( p - 8 )^2 ) ⇒ divide either side by 25r^2,
q^2 / 25r^2 = ( p - 8 )^2 ⇒ Now apply square root on either side,
| p - 8 | = √( q^2 / 25r^2 ) ⇒ Simplify,
| p - 8 | = q / 5r,
| p | = q / 5r + 8,
<em>Answer; p = ± q / 5r + 8; Option D</em>
Answer:
Qa: The heritability for tallness in these crops is 0.08, while Qb: Genes slightly influence the trait for height.
Step-by-step explanation:
Qa: The average height of regular crops grown by the farmer was 5 feet. The amazingly tall breeds have a 3feet increment than the usual crops. This progeny of the farmer's choice breeds has a 0.25 feet increment in height than what is expected in other normal breeds. Therefore, the heritability of the tall trait by these progeny was 0.25/3, which is 0.08333.....Approximately 0.08.
Qb: This low heritability index showed that the trait for tallness is slightly influenced by gene, because if otherwise, the index would have been a far way higher than this. However, we cannot conclude that it is the environment that determines the tall phenotype to be expected in the crops; this renders other options wrong.
Answer:
17 67899887753 o
haggis to get a chance to get a chance
up to you and I don't know how I turned
him to be read by signs or something like that but
Step-by-step explanation:
join us for a while ago and I don't know
Answer:
Converting velocity into m/s
72x5/18=20 m/s²
Distance = Velocity *Time
20*5=100m
Step-by-step explanation:
hope it's helpful
