You are performing a hypothesis test. You have a null hypothesis and an alternate hypothesis. If the test result is not significant, you accept the null hypothesis and reject the alternate hypothesis. That does not mean that you KNOW which hypothesis is true.
Answer:
![B = 38](https://tex.z-dn.net/?f=B%20%3D%2038)
Step-by-step explanation:
This question can be illustrated using the attachment and the required bearing will be calculated using cosine theorem;
![b^2 = a^2 + c^2 - 2ac\ CosB](https://tex.z-dn.net/?f=b%5E2%20%3D%20a%5E2%20%2B%20c%5E2%20-%202ac%5C%20CosB)
In this case:
![b = 5](https://tex.z-dn.net/?f=b%20%3D%205)
![a = 7](https://tex.z-dn.net/?f=a%20%3D%207)
![c = 8](https://tex.z-dn.net/?f=c%20%3D%208)
![](https://tex.z-dn.net/?f=%3CB%20%3D%20%3F%3F)
Substitute these values in ![b^2 = a^2 + c^2 - 2ac\ CosB](https://tex.z-dn.net/?f=b%5E2%20%3D%20a%5E2%20%2B%20c%5E2%20-%202ac%5C%20CosB)
![5^2 = 7^2 + 8^2 - 2 * 7 * 8\ CosB](https://tex.z-dn.net/?f=5%5E2%20%3D%207%5E2%20%2B%208%5E2%20-%202%20%2A%207%20%2A%208%5C%20CosB)
![25 = 49 + 64 - 112\ CosB](https://tex.z-dn.net/?f=25%20%3D%2049%20%2B%2064%20-%20112%5C%20CosB)
![25 = 113- 112\ CosB](https://tex.z-dn.net/?f=25%20%3D%20113-%20112%5C%20CosB)
Collect Like Terms
![25 -113=- 112\ CosB](https://tex.z-dn.net/?f=25%20-113%3D-%20112%5C%20CosB)
![-88=- 112\ CosB](https://tex.z-dn.net/?f=-88%3D-%20112%5C%20CosB)
Divide through by -112
![\frac{-88}{-112}= \frac{- 112\ CosB}{-112}](https://tex.z-dn.net/?f=%5Cfrac%7B-88%7D%7B-112%7D%3D%20%5Cfrac%7B-%20112%5C%20CosB%7D%7B-112%7D)
![\frac{-88}{-112}= CosB](https://tex.z-dn.net/?f=%5Cfrac%7B-88%7D%7B-112%7D%3D%20CosB)
Reorder
![Cos\ B = \frac{-88}{-112}](https://tex.z-dn.net/?f=Cos%5C%20B%20%3D%20%5Cfrac%7B-88%7D%7B-112%7D)
![Cos\ B = 0.7857](https://tex.z-dn.net/?f=Cos%5C%20B%20%3D%200.7857)
Take arccos of both sides
![B = cos^{-1}(0.7857)](https://tex.z-dn.net/?f=B%20%3D%20cos%5E%7B-1%7D%280.7857%29)
![B = cos^{-1}(0.7857)](https://tex.z-dn.net/?f=B%20%3D%20cos%5E%7B-1%7D%280.7857%29)
--- <em>(approximated)</em>
<em>Hence, the bearing is approximately 38 degrees</em>
Answer:
One solution.
Step-by-step explanation:
This is the only way I know how to solve it. These two expressions are equivalent to each other.
Any relation is x and y is said to be a Direct variation if one is a constant multiplier of the other .In other words we can say : when one variable changes the other changes in proportion to the first.
The Direct variation equation are of the type y=k.x
Here k is known as constant of proportionality .It has a fixed value.
The given equation is y=![\frac{k}{6}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bk%7D%7B6%7D%20%20)
If we compare this equation with y=k.x
Then k=![\frac{1}{6}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B6%7D%20%20)
Answer:
At x=3 the value of the function is 4
Step-by-step explanation:
we have the points
(-2,3) and (3,4)
That means
(-2,3)
For x=-2
The value of the function y is equal to 3
(3,4)
For x=3
The value of the function y is equal to 4
therefore
At x=3 the value of the function is 4