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laila [671]
3 years ago
6

An insurance company advertises that 90% of their accident claims are settled within 30 days. A consumer group randomly selects

104 of last year’s claims from the company’s files, and finds that only 89 of them were settled within 30 days. Is the company guilty of false advertising?
Mathematics
1 answer:
Alona [7]3 years ago
4 0

Answer:x

Step-by-step explanation:

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What is six hundred ten thousand in scientific notation
Eva8 [605]
610,000 in scientific notation is: 6.1 x 10^5
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3 years ago
Read 2 more answers
PLEASE HELP!!! WILL GIVE BRAINLIEST!!!
777dan777 [17]

Answer: (2,2) and (-5,16)

Step-by-step explanation:

Here we have both Line (Linear Function) and Parabola (Quadratic Function)

So I am gonna write these equations here,

y=x^2+x-4\\y=-2x+6

The first equation has Parabola graph (Since it's second degree.)

and the second equation has line graph.

To find the intersection, you have to substitute either -2x+6 in first equation (Quadratic) or x^2+x-4 in second equation (Linear)

For me, I am going to substitute x^2+x-4 in y=-2x+6.

x^2+x-4=-2x+6

Now solve the equation and find the value of x.

Since it's Quadratic Equation (Because there's x^2) I'd move -2x+6 to the left side.

x^2+x-4+2x-6=0 Finish things here (Subtract and Addition)

x^2+3x-10=0 What two numbers multiply to 10? Find the factors of 10, that are [1 and 10] and [2 and 5]

Now think about it, do you think that if 1 and 10 subtract or even addition, do you think that it'd be 3? No, of course not.

So 2 and 5 is right.

(x-2)(x+5)=0 (5-2 = 3) and (5*(-2) = -10)

Then we get both x, x=2,-5

However, this is not it. You have to substitute both x in Linear Equation.

Substitute x = 2 in y=-2x+6

y=-2(2)+6\\y=-4+6\\y=2

Order = (2,2)

Then substitute x = -5 in y=-2x+6

y=-2(-5)+6\\y=10+6\\y=16

Order = (-5,16)

So the intersections are both (2,2) and (-5,16) as shown in graph below.

4 0
4 years ago
Factor the binomial.<br> 4z2 − 25<br> 4z2 − 25 =
svetoff [14.1K]

4z^2-25\\\\=(2z)^2-5^2\\\\=(2z+5)(2z-5)

6 0
2 years ago
(1+x^2)dy/dx+2xy-4x^2=0 bu using Bernoulli's Equation
erastovalidia [21]
Not of Bernoulli type, but still linear.

(1+x^2)\dfrac{\mathrm dy}{\mathrm dx}+2xy=4x^2

There's no need to find an integrating factor, since the left hand side already represents a derivative:

\dfrac{\mathrm d}{\mathrm dx}[(1+x^2)y]=(1+x^2)\dfrac{\mathrm dy}{\mathrm dx}+2xy

So, you have

\dfrac{\mathrm d}{\mathrm dx}[(1+x^2)y]=4x^2

and integrating both sides with respect to x yields

(1+x^2)y=\displaystyle\int4x^2\,\mathrm dx
(1+x^2)y=\dfrac43x^3+C
y=\dfrac{4x^3}{3(1+x^2)}+\dfrac C{1+x^2}
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3 years ago
How to solve g(n)=4n-5;Find g(6)
sergey [27]
19 i think though im pretty sure it is
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