3 years ago

Find the first six terms of the sequence. a1 = 4, an = 2 • an-1

1 answer:

8 0

<span>a1 = 4, an = 2 â€˘ an-1 a1 = 4 a2 = 2* a2-1 = 2*a1 = 2*4 = 8 a3 = 2* a3-1 = 2*a2 = 2*8 = 16 a4 = 2* a4-1 = 2*a3 = 2*16 = 32 a5 = 2* a5-1 = 2*a4 = 2*32 = 64 a6 = 2* a6-1 = 2*a5 = 2*64 = 128 The first six terms of the sequence are 4, 8, 16, 32, 64, and 128.</span>

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