The probability of event A and B to both occur is denoted as P(A ∩ B) = P(A) P(B|A). It is the probability that Event A occurs times the probability that Event B occurs, given that Event A has occurred.
So, to find the probability that you will be assigned a poem by Shakespeare and by Tennyson, let Event A = the event that a Shakespeare poem will be assigned to you; and let Event B = the event that the second poem that will be assigned to you will be by Tennyson.
At first, there are a total of 13 poems that would be randomly assigned in your class. There are 4 poems by Shakespeare, thus P(A) is 4/13.
After the first selection, there would be 13 poems left. Therefore, P(B|A) = 2/12
Based on the rule of multiplication,
P(A ∩ B) = P(A) P(B|A)P(A ∩ B) = 4/13 * 2/12
P(A ∩ B) = 8/156
P(A ∩ B) = 2/39
The probability that you will be assigned a poem by Shakespeare, then a poem by Tennyson is 2/39 or 5.13%.
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Answer:
A. 
Step-by-step explanation:
Given:

To find the quotient, we would multiply the first fraction (⅖) by the reciprocal of the second fraction (reciprocal of ¼ = 4).
This, we would have:


Answer:
![[ln \frac{x(x^2 + 1)}{(x + 1)}]^\frac{3}{2}](https://tex.z-dn.net/?f=%5Bln%20%5Cfrac%7Bx%28x%5E2%20%2B%201%29%7D%7B%28x%20%2B%201%29%7D%5D%5E%5Cfrac%7B3%7D%7B2%7D)
Step-by-step explanation:
![\frac{3}{2} [ln x(x^2 + 1) - ln(x + 1)]](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%20%5Bln%20x%28x%5E2%20%2B%201%29%20-%20ln%28x%20%2B%201%29%5D)
ln(m/n)= lnm - ln(n)
![\frac{3}{2}[ln x(x^2 + 1) - ln(x + 1)]](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%5Bln%20x%28x%5E2%20%2B%201%29%20-%20ln%28x%20%2B%201%29%5D)
![\frac{3}{2}[ln \frac{x(x^2 + 1)}{(x + 1)}]](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%5Bln%20%5Cfrac%7Bx%28x%5E2%20%2B%201%29%7D%7B%28x%20%2B%201%29%7D%5D)
3/2 is before ln. so we move the fraction 3/2 to the exponent
as per log property we move the fraction to the exponent
![[ln \frac{x(x^2 + 1)}{(x + 1)}]^\frac{3}{2}](https://tex.z-dn.net/?f=%5Bln%20%5Cfrac%7Bx%28x%5E2%20%2B%201%29%7D%7B%28x%20%2B%201%29%7D%5D%5E%5Cfrac%7B3%7D%7B2%7D)
First I did 8*6 which is 48 ( meaning there is 48 slices total)
Then take 36 and subtract that from 48 getting 12.
So there is 12 slices of pizza left over.