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3 years ago

9

Write the equation of the line with a slope of 17 and passing through the point (0, 0)

1 answer:

Mkey [24]3 years ago

8 0

The equation for a line is y=mx+b. where m is the slope and b is the y intercept.
The slope of 17 is provided. This means m=17. The point (0,0) tells you the y intercept is 0. This means b=0

Plugging these into the equation and simplifying:
y=17x+0

y=17x

Hope this helps :)

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3 years ago

2.<br> Which of the functions below is an inverse of the quadratic function f(x) = x2 - 3 ?

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the inverse of the quadratic function $f(x) = x^2 - 3$ is $\mathbf{f^{-1}(x)=\pm \sqrt{x+3}}$

Step-by-step explanation:

We need to find inverse of the quadratic function $f(x) = x^2 - 3$

Let

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Replace x and y

$x=y^2-3$

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3 years ago

A ball is thrown at an initial height of 7 feet with an initial upward velocity at 27 ft/s. The balls height h (in feet) after t

lianna [129]

Answer:

The height of ball is 17 ft at t=0.55 and t=1.14.

Step-by-step explanation:

The general projectile motion is defined as

$y=-16t^2+vt+y_0$

Where, v is initial velocity and y₀ is initial height.

It is given that the initial height is 7 and the initial upward velocity is 27.

Substitute v=27 and y₀=7 in the above equation to find the model for height of the ball.

$h(t)=-16t^2+27t+7$

The height of ball is 17 ft. Put h(t)=17.

$17=-16t^2+27t+7$

$0=-16t^2+27t-10$

On solving this equation using graphing calculator we get

$t=0.549,1.139$

$t\approx 0.55,1.14$

Therefore the height of ball is 17 ft at t=0.55 and t=1.14.

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