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solong [7]
3 years ago
12

What does -2/3 (x + 5) + 4 (x + 5) - 10/3 (x + 5) equal

Mathematics
1 answer:
Kitty [74]3 years ago
4 0

Answer: 0

Step-by-step explanation:

-\frac{2}{3}(x+5)+4(x+5)-\frac{10}{3}(x+5) = ?

-\frac{2}{3}x-\frac{10}{3}x+4x+20-\frac{10}{3}x-\frac{50}{3} = ?

(-\frac{2}{3}x+4x -\frac{10}{3}x) +(-\frac{10}{3}+20-\frac{50}{3})=?

(-\frac{12}{3}x+4x)+(-\frac{60}{3}+20)=?\\  (-4x+4x)+(-20+20)=?\\0+0=0

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A distribution of scores for a test of life stressors has a mean of µ = 125 and standard deviation of σ = 15. The researcher cal
laila [671]

Answer:

The mean and standard deviation for the z-scores in this distribution are 0 and 1 respectively.

Step-by-step explanation:

Let the random variable <em>X</em> follow a Normal distribution with mean <em>μ </em>and standard deviation <em>σ.</em>

The <em>z</em>-scores are standardized form of the raw scores <em>X</em>. It is computed by subtracting the mean (<em>μ</em>) from the raw score <em>x</em> and dividing the result by the standard deviation (<em>σ</em>).

z=\frac{x-\mu}{\sigma}

These <em>z</em>-scores also follow a normal distribution.

The mean is:

E(z)=E[\frac{x-\mu}{\sigma} ]=\frac{1}{\sigma}\times [E(x)-\mu] =\frac{1}{\sigma}\times [\mu-\mu]=0

The standard deviation is:

Var(z)=Var[\frac{x-\mu}{\sigma} ]=\frac{1}{\sigma^{2}}\times [Var(x)-Var(\mu)] =\frac{\sigma^{2}-0}{\sigma^{2}}=1\\SD(z)=\sqrt{Var(z)}=1

Thus, the mean and standard deviation for the z-scores in this distribution are 0 and 1 respectively.

8 0
3 years ago
QUICK WILL GIVE BRAINLIEST.
Darina [25.2K]

Answer:

-5

Step-by-step explanation:

here u go! hope i got it fast enough!

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x  y        x2 y2

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