Answer:
#include <stdio.h>
int main()
{
for (int n = 12; n > 0; n--) {
printf("%d x 2 = %d\n", n, n * 2);
}
}
Explanation:
Only one loop.
Answer:
The result of the following code will be 9
Explanation:
There are several operators used in Python to do mathematical calculations.
** operator is used for exponents.
i.e.
a ** b mathematically means a^b
Here in the given code
3 is assigned to numA and 2 is assigned to numB
Result will be equal to 3^2
Hence,
The result of the following code will be 9
Explanation:
software must be used by well trained staff.
In a block in a blockchain, a resource which represent the transactional data, sender, receiver, and number of coins is: A. data.
<h3>What is a blockchain?</h3>
A blockchain can be defined as a digital and dynamic financial system that is designed and developed to be used in recording and maintaining transactions that are associated with or made through the use of a bitcoin, usually as a database containing various set of data.
In this context, we can infer and logically deduce that data is a resource that typically represent all of the transactional data, sender, recipient (receiver), and the number of bitcoins in a block in a blockchain.
Read more on blockchain here: brainly.com/question/25700270
#SPJ1
Answer:
The sum of all positive even values in arr
Explanation:
We have an array named arr holding int values
Inside the method mystery:
Two variables s1 and s2 are initialized as 0
A for loop is created iterating through the arr array. Inside the loop:
num is set to the ith position of the arr (num will hold the each value in arr)
Then, we have an if statement that checks if num is greater than 0 (if it is positive number) and if num mod 2 is equal to 0 (if it is an even number). If these conditions are satisfied, num will be added to the s1 (cumulative sum). If num is less than 0 (if it is a negative number), num will be added to the s2 (cumulative sum).
When the loop is done, the value of s1 and s2 is printed.
As you can see, s1 holds the sum of positive even values in the arr
