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The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out

Whitepunk [10]

Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So $p = 0.3723$

12 games in November

So $n = 12$

What is the probability that the hockey team wins 6 games in November?

This is $P(X = 6)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505$

0.1505 = 15.05% probability that the hockey team wins 6 games in November

4 0

2 years ago

What the answer to this

MatroZZZ [7]

Answer: D

Used my graphic calculator

5 0

3 years ago

The bells at Kings School ring every 6 minutes. At Queens School the bells ring every 5 minutes. At Princess School the bells ri

Mamont248 [21]

The bells will ring together again at 10:00am I believe.

7 0

3 years ago

Read 2 more answers

Which solution to the equation 1/x-1 = x-2/2x^2-2 is extraneous

melamori03 [73]

Solution-

The equation given here,

$\frac{1}{x-1} =\frac{x-2}{2x^2-2}$

$\Rightarrow 2x^2-2=(x-1)(x-2)$

$\Rightarrow 2x^2-2=x^2-3x+2$

$\Rightarrow x^2+3x-4=0$

$\Rightarrow x^2 +4x-x-4=0$

$\Rightarrow (x-1)(x+4)=0$

$\Rightarrow x=1 \ and -4$

But, at x=1, $\frac{1}{x-1} \ and \ \frac{x-2}{2x^2-2}$ becomes infinity so it can't be a solution to the equation.

∴ x=1 is the extraneous solution of the equation

3 0

3 years ago

Read 2 more answers

Which expression is equivalent to (16x^8y^-12)^1/2

MAVERICK [17]

Answer:

The equivalent expression is $\Rightarrow \dfrac{4x^4}{y^6}$

Step-by-step explanation:

Given: $(16x^8y^{-12})^{1/2}$

We need to simplify the expression. We will distribute radical with each term inside the parentheses.

$\Rightarrow (16x^8y^{-12})^{1/2}$

Distribute the radical

$\Rightarrow 16^{1/2}\cdot x^{8\cdot 1/2\cdot y^{-12\cdot 1/2}$

$\Rightarrow 4\cdot x^4\cdot y^{-6}$

$\Rightarrow 4x^4y^{-6}$

Now we will simplify the negative exponent.

$\Rightarrow \dfrac{4x^4}{y^6}$

Hence, The equivalent expression is $\Rightarrow \dfrac{4x^4}{y^6}$

8 0

2 years ago