Answer:
we will fail to reject the null hypothesis and conclude that the mean pressure is not different from 4.7 psi
Step-by-step explanation:
Let's first define the hypothesis;
Null hypothesis: H0: μ = 4.7
Alternative hypothesis: Ha: μ ≠ 4.7
We have;
Sample size; n = 110
Sample mean; x¯ = 4.6
Variance: σ² = 0.64
Standard deviation; σ = √0.64 = 0.8
Formula for test statistic is;
z = (x¯ - μ)/(σ/√n)
z = (4.6 - 4.7)/(0.8/√110)
z = -0.1/0.0763
z = -1.31
From online p-value from z-score calculator attached, using; z = -1.31, two tailed hypothesis, significance value of 0.1, we have;
P-value = 0.190196
The p-value is greater than the significance value and thus we will fail to reject the null hypothesis and conclude that the mean pressure is not different from 4.7
σ μ
Answer:
the answer of the question is 4e^2 + 17/18
Um I'm good that looks so confusing sorry. TwT
7. 3/5 = 4.5/x
3x= 5(4.5)
x = 15/2
8. 6/4 = 9/x
6x= 45
x= 15/2
8. since triangle ABC and ADE are identical,
angle E is also 30 degrees
so angle D = 180-(30+70)=80 degrees
9. 9/3 = x/5
3x = 45
x = 45/3 = 15
Answer: a. 0.1031; fail to reject the null hypothesis
Step-by-step explanation:
Given: Significance level : 
The test statistic in a two-tailed test is z = -1.63.
The P-value for two-tailed test :
[By p-value table]
Since, 0.1031 > 0.05
i.e. p-value > 
So, we fail to reject the null hypothesis. [When p<
then we reject null hypothesis ]
So, the correct option is a. 0.1031; fail to reject the null hypothesis.