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Nesterboy [21]
3 years ago
14

Which of the following represents the tang of the graph of F(x) below

Mathematics
1 answer:
dexar [7]3 years ago
6 0

The range of function is Z_F=\{y\in\mathbb{R}\wedge y\leq2\}.

The answer is B.

Hope this helps.

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13x+5y=90 what is x? what is y?
Leona [35]

Answer:

X=-5y/13+90/13, Y=-13x/5+18

Step-by-step explanation:

You need to solve the equation for X and Y.

Solving for X:

13x+5y=90

Subtract 5y: 13x=-5y+90

Divide by 13: x=-5y/13+90/13

--

For Y:

13x+5y=90

Subtract 13x: 5y=-13x+90

Divide by 5: y=-13x/5+90/5

(Simplifies to -13x/5+18)

3 0
3 years ago
A new cruise ship line has just launched 3 new​ ships: the Pacific​ Paradise, the Caribbean​ Paradise, and the Mediterranean Par
topjm [15]
Let the number of deluxe that Pacific has be x
the number that Caribbean has will be (x+18)
the number that Mediterranean has will be (3x-25)
total b=number of deluxe in the 3 ships will be:
x+(x+18)+(3x-25)
5x-7=928
5x=928+7
x=935/5
x=187
Hence the Pacific has 187, Caribbean has 187+18=205, Mediterranean has (3*187-25)
=534 
6 0
3 years ago
I need help with this?? Anyone?
sergey [27]
- Question -

Which statement about solving inequalities is true?

- Answer -

A)

Adding the same value to both sides of an inequality does not change the solution set.


- The Wolf -
3 0
3 years ago
Read 2 more answers
At the fair, 220 balloons are given to 40 children, 3/8 of whom are girls. Each boy receives the same number of balloons. Each g
mixer [17]

Po
Methane(CH4)
Ethane(C2H6)
Propane(C3H8)
Butane(C4H10)
Pentane(C5H12)
Hexane(C6H14)
Jul 3, 2018
http://www.gcesystems.com › what-...
5 0
2 years ago
From the lighthouse 1000 ft above sea level the angle of depression to boat a is 29 degress.a little bit later the boat moved cl
AnnyKZ [126]

Answer: The boat moved 768.51 feet  in that time .

Step-by-step explanation:

Since we have given that

Height of the lighthouse = 1000 feet

Angle depression to boat 'a' = 29°

Angle of depression  to shore 'b' = 44°

Consider ΔABC,

\tan 44\textdegree=\frac{AB}{BC}\\\\\tan 44\textdegree=\frac{1000}{BC}\\\\BC=\frac{1000}{\tan 44\textdegree}\\\\BC=1035.53\ feet

Now, Consider, ΔABD,

\tan 29\textdegree=\frac{AB}{BD}\\\\\tan 29\textdegree=\frac{1000}{BD}\\\\BD=\frac{1000}{\tan 29\textdegree}\\\\BD=1804.04\ feet

We need to find the distance that the boat moved in that time i.e. BC

so,

DC=BD-BC\\\\CD=1804.04-1035.53\\\\CD=768.51\ feet

Hence, the boat moved 768.51 feet  in that time .

6 0
3 years ago
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