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3 years ago

8

Rebecca bought groceries using 50% of her paycheck from her part time job. She saved 75% of the remaining amount of money and ha

d $60 left. What was the amount of Rebecca's paycheck?

1 answer:

never [62]3 years ago

8 0

0.75 (1/2x) = 60

60/3 is 20, which is 25% of her remaining money,
So her total remaining money is $80.

Then 80 x 2 = 160

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Is this correct or no <br><br> Please help me

k0ka [10]

Answer:

I got y = 10

or

y = 24

or the answer is y = -5x since the 4 stays the same but the -5x changes

I feel like you have to replace with x with the numbers

Step-by-step explanation:

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3 years ago

David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o

BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :( $b^4,b^2,b^4$ )

$b^4$ = b × b × b × b

$b^2$ = b × b

$b^4$ =b × b × b × b

GCF of variables :( $b^4,b^2,b^4$ ) is $b^2$

3) GCF of $c^3$ and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) $80b^4-32b^2c^3+48b^4c$

$=16b^2(5b^2-2c^3+3b^2c)$

David applied the distributive property.

7 0

2 years ago

Read 3 more answers

A swimming pool at a park measures 9.75 meters by 7.2 meters.

neonofarm [45]

Answer:

Part a) The area of the swimming pool is $70.2\ m^2$

Part b) The total area of the swimming pool and the playground is $105.3\ m^2$

Step-by-step explanation:

Part a) Find the area of the swimming pool

we know that

The area of the swimming pool is

$A=LW$

where

L is the length side

W is the width side

we have

$L=9.75\ m\\W=7.2\ m$

substitute the values

$A=(9.75)(7.2)$

$A=70.2\ m^2$

therefore

The area of the swimming pool is $70.2\ m^2$

Part b) The area of the playground is one and a half times that of the swimming pool. Find the total area of the swimming pool and the playground

we know that

To obtain the area of the playground multiply the area of the swimming pool by one and a half

$\frac{1}{2}(70.2)=35.1\ m^2$

To obtain the total area of the swimming pool and the playground, adds the area of the swimming pool and the area of the playground

so

$70.2\ m^2+35.1\ m^2=105.3\ m^2$

therefore

The total area of the swimming pool and the playground is $105.3\ m^2$

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3 years ago

Factor Completely'''

vekshin1

Answer:

$4x^2(x-2)(x+6)$

Step-by-step explanation:

Factor $4x^2$

$4x^2(x^2)+4x^2(4x)-4x^2(-12)$

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<em>good luck, hope this helps :)</em>

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Mekhanik [1.2K]

Answer:

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Step-by-step explanation:

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