Answer:
Step-by-step explanation:
The area of a rectangle is given by 
. Therefore, we can set up the following inequality:
.
Solving this inequality, we have:
.
Therefore, the largest length Carmen's painting can be is 
.
He’s right For the answer
If you draw a rectangle divided up into eight even parts, and label them each as 1/8, then you can show your work for how you double it. You do this by "coloring" one in, and then doing the same for a second piece (but color that one in a different way). You can visually double an eighth in that way.
Or, you can simply multiply by 2 to double 1/8:
1/8x2/1=2/8
This problem can be looked at like a right triangle, where the hypotenuse is 750 and one leg is 450. Thus 450^2 + the length of the park^2 = 750 ^2.
202500 + the length of the park^2 = 562500
the length of the park^2 = 360000
the length of the park = 600
Hope it helps <3
