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nexus9112 [7]
3 years ago
5

Help me with number 3

Mathematics
1 answer:
love history [14]3 years ago
8 0
Well on front, you see 2 x 4 cereal boxes and it has depth of 3 cereal boxes.

So that would be 2×4×3 = 24 cereal boxes in total.

Since each cereal box is 175 in³, that would be 24 × 175 in³ = 4200 in³

So the answer is D.
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(05.02)A doghouse is to be built in the shape of a right trapezoid, as shown below. What is the area of the doghouse?
ira [324]

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iuhiyugyuguyguygtugtugtufytfutuygfryuhtriubntuoeibngriuoirntutyrnytn

Step-by-step explanation:

4 0
2 years ago
What is the common ratio for the geometric sequence?<br><br> 35/2, 7, 14/5, 28/25, ..…
LiRa [457]

Answer:

2/5

Step-by-step explanation:

8 0
3 years ago
Help me check my answer!
astra-53 [7]

Step-by-step explanation:

ah, here you go.

come on, now. you know this now ...

again, mutually exclusive attributes in the table (no overlap here) allow us to add the numbers for a total :

4+2+12+10 = 28 students in total.

how many of those 28 fulfill our desired criteria (has a brother) ?

well, it is the sum of the column "has a brother", as it does not matter, if there is also a sister or not.

so, it is 4 + 12 = 16

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5 0
2 years ago
During the first four months of the year, Jack earned $1270, $1150, $870 and $1450 If Jack must have an average salary of at lea
tia_tia [17]

Answer:

1010

Step-by-step explanation:

There are a whole class of questions that rely on the method to this one.

First add up what you know

1270 + 1150 + 870 + 1450 = 4740

Now add on the 5th month (which you don't know. Call it x)

4740 + x

Divide by 5

(4740 + x)/5 = 1150 and that is your equation    

Solution

Multiply both sides by 5

5*(4740 + x) / 5 = 1150 * 5

4740 + x = 5750

Subtract 4740 from both sides

4740 - 4740 + x = 5750 - 4740

x = 1010

Which seems kind of low, but that's what the numbers come to.

6 0
3 years ago
Unlike fractions 5/6-1/2=
PolarNik [594]
The answer is one third or 1/3 multiply diagonal both ways and then multiply  denominators 
5 0
3 years ago
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