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2 years ago

The area of a rectangular pool is 6365 m2. If the length of the pool is 95 m, what is its width?

Mathematics

1 answer:

PilotLPTM [1.2K]2 years ago

3 0

Answer:

6365/95 = 67

But if your counting METERS and SQUARE METERS

It would be 134

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For which sample size (n) and sample proportion (p) can a normal curve be

Nonamiya [84]

Answer:

Option c.

Step-by-step explanation:

Using the normal curve to approximate a sampling distribution:

For a sample size n and a proportion n, the normal curve can be used if:

$np \geq 10$ and $n(1-p) \geq 10$

Option a:

$np = 35*0.8 = 28 > 10$

$n(1-p) = 35*0.2 = 7 < 10$

So option a cannot be used.

Option b:

$np = 65*0.9 = 58.5 > 10$

$n(1-p) = 65*0.1 = 6.5 < 10$

So option b cannot be used.

Option c:

$np = 65*0.8 = 52 > 10$

$n(1-p) = 65*0.2 = 13 > 10$

So option c can be used, and is the answer

Option d:

$np = 35*0.9 = 31.5 > 10$

$n(1-p) = 35*0.1 = 3.5 < 10$

So option d cannot be used.

The answer is given by option c.

7 0

3 years ago

Use slopes and y-intercepts to determine if the lines 5x-5y=-2 and -x+2y=4

HACTEHA [7]

The given pair of lines are not perpendicular.

The line is a curve showing the shortest distance between 2 points.

5x - 5y = -2 - - - - - (1)
Transform the equation into standard form,
5x + 2 = 5y
y = 5x /5 + 2/5
y = x + 2/5

The slope of equation 1 is $m_1 = 1$ and intercept c = 2 / 5

Similarly
x + 2y = 4 - - - - - - - -(2)
Transform it into standard form
y = -x/2 + 4 /2
y = -x / 2 + 2

Slope of the equation 2 $m_2$ = -1 / 2 and intercept c = 2
Slope of line 1 * slope of line 2 = 1 * -1/2 = -1/2

Since the lines are not perpendicular because the pair of lines does not satisfy the property of perpendicular lines i.e
$m_1*m_2 = -1$

Thus, the given pair of lines are not perpendicular.

Learn more about lines here:

brainly.com/question/2696693

#SPJ1

6 0

1 year ago

You are trying to heat up a cup of water with a butane lighter.

algol13

Answer:

Step-by-step explanation:

Remark

The formula for this is

Heat = m * c * Δt

Givens

Heat = unknown

m = 200 grams

c = 4.184 Joules / grams oC

Δt = the change in temperature = 35.7 - 22.3 = 13.4

Solution

Heat = 200 * 4.184 * 13.4

Heat = 11213 Joules

Heat = 11.2 Kj

It's hard to get the correct number of sig digs because the 200 is not qualified in any way.

Part 2.

This can really puzzle you until you know that heat given up = the heat taken on. The heat taken on was 11.2 Kj. The Butane lighter must have given that heat on.

Heat of Combustion = Heat Given Up / Number grams burned.

Heat of Combustion = 11.2 Kj / 0.23 grams

Heat of Combustion = 48.8 Kj / gram

8 0

2 years ago

Please help me i have a test in 15 minutes please say a b c or d it’s the top one

ivanzaharov [21]

Its b !!!!!!!!!!!!!!!!!!!!!!!!!!!!!

6 0

2 years ago

Can you Afford to Enlarge this?You each want to have a 3" X 5' picture ofprinted so that you canput it on your dartboard. It cos

Marizza181 [45]

Given:

$\text{ Dimension = 3}\times5$

Sol:

Area of picture is:

$\begin{gathered} =\text{ length}\times\text{ Width} \\ \\ =15 \end{gathered}$

If the cost $10 per square inch then price of 15 square inch is:

$\begin{gathered} =15\times10 \\ \\ =150 \end{gathered}$

If the quadruple of dimension that mean:

$\begin{gathered} \text{ l ength = 4 length} \\ \\ Width\text{ = 4 width} \end{gathered}$

So area is:

$\begin{gathered} A=4\text{ length}\times4\text{ Width} \\ \\ A=4(15) \\ \\ A=60 \end{gathered}$

So price is:

$\begin{gathered} =60\times10 \\ \\ =600 \end{gathered}$

3 0

8 months ago