Given: m || n, ∠1 ≅ ∠3 Prove: p || q Horizontal parallel lines n and m are cut by transversals q and p. At the intersection of l
ines q and m, the uppercase right angle is angle 3. At the intersection of lines p and m, the uppercase right angle is angle 2. At the intersection of lines p and n, the bottom left angle is angle 1. Complete the two-column proof. ♣ = ♦ = ♠ =
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Solution: For a positively skewed distribution with a mean of m=20, the most probable value for the median is less than 20.
<u>Explanation:</u>
We know that in a symmetric distribution, the relationship between mean, median and mode is:
In case of negatively skewed distribution, the relationship between mean,median and mode is:
In case of positively skewed distribution, the relationship between mean,median and mode is:
Therefore, for a positively skewed distribution with a mean of m = 20, the median would be less than Mean. Hence the probable value of median is less than 20