Question

Help on this problem?? please?

Answer 1

MrBillDoesMath!

Answer to #4:  81/256 * s^8 * t^ 12

Comments:

(7x^3) ^ (1/2)   =  7 ^ (1/2)  *  x^(3/2)   where  ^(1/2) means the square root of a quantity. The answer written (7x^3) is NOT correct.

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(1)             (27s^7t^11)^ (4/3)  

               = 27^(4/3) * (s^7)^(4/3) * (t^11)^ (4/3)

As 27 = 3^3, 27 ^(4/3) = 3^4 = 81

               

(2)  (-64st^2)^ (4/3)  =     (-64)^(4/3) * (s^4/3) * t(^8/3)

As 64 = (-4)^3,  (-64)^(4/3) = (-4)^4 = +256                                        

So (1)/(2) =

81 * s^(28/3)* t^(44/3)

-------------------------------     =

256 s^(4/3) * t^((8/3)

81/256 *  s ^ (28/3 - 4/3) * t^(44/3 - 8/3) =

81/256 * s^(24/3) * t (36/3) =

81/256 * s^8        * t^ 12

MrB