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3 years ago

How to find the midpoint using coordinates A(-1,5), B(2,-3)

2 answers:

5 0

The midpoint formula is (x1+x2)/(2),(y1+y2)/(2). The coordinates will be substituted into this formula: (-1+2)/(2), (5+-3)/(2). This simplifies to (1/2,1). This is the midpoint. Hope this helped!

Alex Ar [27]3 years ago

4 0

Count the line and the distance between them

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Given f(x) = 3x^3 - 4x^2 + x - 1 , what is f(2) ?

Yakvenalex [24]

2 will replace each x on the right

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3 years ago

What is the radius of a circle whose equation is X^2 plus Y^2 -10X +6 X +18=0?

frosja888 [35]

ANSWER

The radius is 4

EXPLANATION

The given equation is:

${x}^{2} + {y}^{2} - 10y + 6x + 18 = 0$

We complete the square to get the expression in standard form:

${x}^{2} + 6x + {y}^{2} - 10y + 18 = 0$

${x}^{2} + 6x + 9 + {y}^{2} - 10y + 25 = - 18 + 9 + 25$

We factor using perfect squares to get:

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This implies that,

${(x + 3)}^{2} + {(y - 5)}^{2} = {4}^{2}$

Comparing to

${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

The radius is r=4

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