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2 years ago

How to find the midpoint using coordinates A(-1,5), B(2,-3)

2 answers:

5 0

The midpoint formula is (x1+x2)/(2),(y1+y2)/(2). The coordinates will be substituted into this formula: (-1+2)/(2), (5+-3)/(2). This simplifies to (1/2,1). This is the midpoint. Hope this helped!

Alex Ar [27]2 years ago

4 0

Count the line and the distance between them

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Ayo help me please<br><br> 4 5/6 x 2/5

Law Incorporation [45]

Answer:

19.3333333

Step-by-step explanation:

You make an improper fraction and multiply

3 0

2 years ago

Read 2 more answers

Create a polynomial function in factored form that has the following characteristics: zero at x = 1, multiplicity of 2; zero at

Nataliya [291]

$(x-1)^{2} (x+2)$

3 0

3 years ago

1. From 1992 to 2007 the average home price increased by 8% per year. In 1992 Anita Bath

Anuta_ua [19.1K]

Answer:

Anita Bath's home was worth $ 593,195.62 in 2007.

Step-by-step explanation:

Given that from 1992 to 2007 the average home price increased by 8% per year, and in 1992 Anita Bath bought a house for $ 187,000, to determine what was it worth in 2007 the following calculation must be performed:

2007 - 1992 = 15

187000 x 1.08 ^ 15 = X

187000 x 3.172 = X

593,195.62 = X

Therefore, Anita Bath's home was worth $ 593,195.62 in 2007.

5 0

2 years ago

PLEASE HELP I DO NOT UNDERSTAND AT ALL ITS PRECALC PLEASE SERIOUS ANSWERS

Elina [12.6K]

You want to end up with $A\sin(\omega t+\phi)$ . Expand this using the angle sum identity for sine:

$A\sin(\omega t+\phi)=A\sin(\omega t)\cos\phi+A\cos(\omega t)\sin\phi$

We want this to line up with $2\sin(4\pi t)+5\cos(4\pi t)$ . Right away, we know $\omega=4\pi$ .

We also need to have

$\begin{cases}A\cos\phi=2\\A\sin\phi=5\end{cases}$

Recall that $\sin^2x+\cos^2x=1$ for all $x$ ; this means

$(A\cos\phi)^2+(A\sin\phi)^2=2^2+5^2\implies A^2=29\implies A=\sqrt{29}$

Then

$\begin{cases}\cos\phi=\frac2{\sqrt{29}}\\\sin\phi=\frac5{\sqrt{29}}\end{cases}\implies\tan\phi=\dfrac{\sin\phi}{\cos\phi}=\dfrac52\implies\phi=\tan^{-1}\left(\dfrac52\right)$

So we end up with

$2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)$

8 0

2 years ago

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What is the solution to the equation fraction 1 over 4x = 5?

AVprozaik [17]

$\displaystyle \frac{1}{4x}=5\quad \Big|\cdot 4x\\\\1=20x\quad\Big|:20\\\\x= \frac{1}{20}$

7 0

2 years ago