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Harrizon [31]
3 years ago
7

The distance AND midpoint between M (-2,5) and p (7,-3)

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0

Answer:

Distance: 12.04159458 or 12.0

Midpoint: (2.5, 1)

Step-by-step explanation:

I used the Distance and the Midpoint Formulas.



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For every left handed person, rhere are about 4 right handed people. If there are 30 students in a class, predoct the number of
hjlf

Answer:

4 right handlers for everytime 5 people

solution:

4/5. = x/30

x = (4)(30)/5

x= 24

there are 24 right handed people

Step-by-step explanation:

I am left handed so I know this is true :)

7 0
11 months ago
What is the quotient when 0.75 is divided by 5?
tensa zangetsu [6.8K]
0.15
(its just 0.75 ÷ 5)
5 0
3 years ago
Read 2 more answers
1. In how many different ways can 5 people be seated at a round table?
Alexeev081 [22]
1. 

Assume the people A, B, C, D and E are sitting in a row.

since there are 5 positions, they can sit in 5*4*3*2*1=120 ways.

consider 1 certain sitting position, for example ABCDE, that is B has A to his right, C to his left. D has C to his right and E to his left. And so on.

the positions 

ABCDE
BCDEA
CDEAB
DEABC
EABCD

while in a row are different positions, in a round table they are the same thing.

(read the letters starting from A, and when the letters finish, continue reading from the beginning of the row. They all read "ABCDE")

This means that any arrangement in a round table, is converted to 5 arrangements in a row.

So there are in total  \frac{5!}{5}=4*3*2*1=24 arrangements of 5 people around a table.

2. check picture.

Consider the case where A is at (2, 2) and B is at (5, 6)

A can move to B through 3 horizontal units to the right, we call them E (for East) and 4 vertical units up, which we call N (for north).

the total path is 7 units.

it can be done in several ways, for example:

ENNNENE (the red path shown in the figure)
NNEEENN (the black path shown in the figure)

In total there are 
\frac{7!}{3!*4!}= \frac{7*6*5*4!}{3!*4!}= \frac{7*6*5}{3!}= 35 paths.

Remark: 7! is the number of arrangements if the letters were different. We divide by 3! because of the 3 E's and 4! because of the 4 N's. 

Another possibility could be A'(3, -5), B'(8,-3).

From A' to B' we go by a total of 5 E and 2 N, so there are 

\frac{7!}{2!*5!}= \frac{7*6*5!}{2!*5!}= \frac{7*6}{2}= 42 paths in total.
there is one more possibility
\frac{7!}{1!(6!)}=7

C.

a) consider the letters {V,E,C,T,O,R}

we can form 6*5*4*3*2*1=720 words, as the first digit can be any of the 6 letters, combined with 5 for the second letter and so on.

b) the difference with a is that we have 5 letters and we have 2 T.

we have in total 5*4*3*2*1=120 arrangements of these letters, if the 2 T's were considered as separate.

consider the arrangements:

T_1RUST_2 and T_2RUST_1.

We read bth as just TRUST, but the permutation formula 5*4*3*2*1 considers these as 2 different.

this is why we need to divide 120 by 2, to get the actual number of words that can be formed. So the number is 60.

Answers:

1) 24

2) 7, 35 or 42. it depends on the positions of A and B, check the solution

3) a-720, b-160
 

8 0
3 years ago
4. A study of 30 fathers was completed in which the fathers were asked the highest level of education they had completed. 10 com
zaharov [31]

Answer:

The cumulative percentage of fathers who completed only elementary school is nearle 33%.

Step-by-step explanation:

Among 30 fathers:

  • 10 completed only elementary school;
  • 10 completed elementary school and high school;
  • 7 completed elementary school, high school and college;
  • 3 completed elementary school, high school, college and graduate school.

You can fill these numbers into the table:

\begin{array}{cccc}&\text{Frequency}&\text{Cumulative frequency}&\text{Cumulative percentage}\\\text{Elementary school}&10&10&\approx 33\%\\\text{El. and high school}&10&20&\approx 67\%\\\text{El., high schools and college}&7&27&90\%\\\text{El., high, college and grad. sch.}&3&30&100\%\end{array}

The cumulative percentage of fathers who completed only elementary school is nearle 33%.

7 0
2 years ago
Lamar sold t-shirts and hats at a festival. He made a $4 profit for each t-shirt he sold. he also made a profit of $34 from sell
galben [10]

Answer:

18 t-shirts.

Step-by-step explanation:

Trey made a total profit $106 by selling t-shirts and hats. $34 of that profit was from selling hats, subtract 34 from 106 and you will get 72. So he made a profit of $72 in selling t-shirts. The t-shirts were $4 each, so if you divide 72 by 4 you will get 18. Meaning he sold 18 shirts.

3 0
2 years ago
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