3 years ago

Which is not an equation of the line going through (6, 7) and (2,-1)?

Mathematics

1 answer:

atroni [7]3 years ago

3 0

Answer:

B. y-1=2(x+2)

Step-by-step explanation:

be the points (6,7) and (2,-1)

replacing 7-1=2(6+2) → 6≠16 and -1-1=2(2+2) → -2≠8

for all equations the equalities are maintained

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The lengths of the diagonals of a rhombus are 4x and 8x. What algebraic expression gives the perimeter of the rhombus?

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Step-by-step explanation:

Use pythagorean formula. In a rhombus the diagonals bisect each other and they are perpendicular, so you could have a right triangle with legs of 2x and 4x, the hypoteneuse would then be $\sqrt{(2x)^{2} +(4x)^{2} }= \sqrt{4x^{2} +16x^{2}}$ which is approximately 4.47x. In a rhombus all 4 sides are the same, so multiply that by 4 and you get the perimeter. 4(4.47x) = 17.88x or if you simplify the radical instead it's $8x\sqrt{5}$