The mass of the sun is about 2×10expont 30 kilograms how many kilograms are in one metric ton

if 1 000 bottles of an award-winning wine are to be packed in special gift boxes which can hold six bottles each, calculate how

Anuta_ua [19.1K]

Step-by-step explanation:

Introduction:

This section basically dedicated to the classification of the antennas which are used in different wavelength.

Wire Antennas:

Wire antennas are familiar to the layman because they are seen virtually everywhere on automobiles, buildings, ships, aircraft, spacecraft, and so on.

There are various shapes of wire antennas such as a straight wire (dipole), loop, and helix which are shown in Figure 1.3.

Loop antennas need not only be circular.

They may take the form of a rectangle, square, ellipse, or any other configuration.

The circular loop is the most common because of its simplicity in construction

Aperture Antennas

Aperture antennas may be more familiar to the layman today than in the past because of the increasing demand for more sophisticated forms of antennas and the utilization of higher frequencies.

Some forms of aperture antennas are shown in Figure 1.4.

Antennas of this type are very useful for aircraft and spacecraft applications, because they can be very conveniently flush-mounted on the skin of the aircraft or spacecraft. In addition, they can be covered with a dielectric material to protect them from hazardous conditions of the environment.

Microstrip Antennas

Microstrip antennas became very popular in the 1970s primarily for spaceborne applications.

Today they are used for government and commercial applications. These antennas consist of a metallic patch on a grounded substrate.

The microstrip antennas are low profile, comformable to planar and nonplanar surfaces, simple and inexpensive to fabricate using modern printed-circuit technology, mechanically robust when mounted on rigid surfaces, compatible with MMIC designs, and very versatile in terms of resonant frequency, polarization, pattern, and impedance.

These antennas can be mounted on the surface of high-performance aircraft, spacecraft, satellites, missiles, cars, and even handheld mobile telephones

Array Antennas

Many applications require radiation characteristics that may not be achievable by a single element. It may, however, be possible that an aggregate of radiating elements

in an electrical and geometrical arrangement (an array) will result inthe desiredradiation characteristics.

The arrangement of the array may be such that the radiation from the elements adds up to give a radiationmaximum ina particular directionor directions, minimum in others, or otherwise as desired.

Typical examples of arrays are shownin Figure 1.6.

Usually the term array is reserved for an arrangement in which the individual radiators are separate as shown in Figures 1.6(a/c).

However the same term is also used to describe an assembly of radiators mounted on a continuous structure, showninFigure 1.6(d).

6 0

2 years ago

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The pair of square pyramids are similar. Use the given information to find the scale factor of the smaller square pyramid to the

Mrrafil [7]

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array}\\\\
-----------------------------$

$\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
\stackrel{\stackrel{pyramids}{scale~factor}}{\cfrac{small}{large}}\qquad \qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{64}}{\sqrt[3]{343}}\implies \cfrac{s}{s}=\cfrac{4}{7}\implies 4:7$

8 0

3 years ago

Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3√5 , KE = 8, LM:KN = 3:5 Find: KM, LM, KN, Area of KLMN

lora16 [44]

Q1)Find KM
As ME is perpendicular to KN, ∠KEM is a right angle
Therefore ΔKEM is a right angled triangle
KE is given and and ME is also given, we need to find KM
for this we can use Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides.
KM² = KE² + ME²
KM² = 8² + (3√5)²
= 64 + 9x5
KM = √109
KM = 10.44

Q2)Find LM
It is said that ratio of LM:KN is 3:5
Therefore if we take the length of one unit as x
length of LM is 3x
and the length of KN is 5x
KN is greater than LM by 2 units
If we take the figure ∠K and ∠N are equal.
Since the angles on opposite sides of the bases are equal then this is called an isosceles trapezoid. So if we draw a line from L that cuts KN perpendicularly at D, ΔKEM and ΔLDN are congruent therefore KE = DN
since KN is greater than LM due to KE and DN , the extra 2 units of KN correspond to 16 units
KN = LM + 2x
2x = KE + DN
2x = 8+8
x = 8
LM = 3x = 3*8 = 24

Q3)Find KN
Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have;
same height ME = LD perpendicular distance between the 2 parallel sides
same right angle when the perpendicular lines cut KN
∠K = ∠N
when 2 angles and one side of one triangle is equal to two angles and one side on another triangle then the 2 triangles are congruent according to AAS theorem (AAS). Therefore KE = DN
the distance ED = LM
Therefore KN = KE + ED + DN
since ED = LM = 24
and KE + DN = 16
KN = 16 + 24 = 40
another way is since KN = 5x and x = 8
KN = 5 * 8 = 40

Q4)Find area KLMN
Area of trapezium can be calculated using the following general equation
Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)
where perpendicular height - ME
2 parallel sides are KN and LM
substituting values into the general equation
Area = 1/2 * ME * (KN+ LM)
= 1/2 * 3√5 * (40 + 24)
= 1/2 * 3√5 * 64
= 3 x 2.23 * 32
= 214.66 units²

8 0

3 years ago

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Whats the mean absolute deviation of 2 2 2 2 2 2 2 2

saveliy_v [14]

Answer:

mad is 0

Step-by-step explanation:

what type of question is this? no offense

6 0

2 years ago

Big ideas math cumulative practice

worty [1.4K]

There are 30 kids in the class and 6 voted for Sunday which means that there is a 6/30 chance that the student picked Sunday or a 20% chance the kid picked Sunday.

8 0

4 years ago