Answer:
See explanation.
(Before continuing reading, I took the base to be 3. Please tell me if you didn't want the base to be 3.)
Step-by-step explanation:
I assume 3 is suppose to be the base. Let's list some values that can be written as 3 to some integer.
3^0=1
3^1=3
3^2=9
3^3=27
3^4=81
3^5=243
......
I could have also did negative integer powers, but this is all I really need to convince you that log_3(28) is between 3 and 4.
log_3(28) means the value x such that 3^x=28.
Since 28 is between 27 and 81 in my list above, that means 3^x is between 3^3 and 3^4. This means that x is a value between 3 and 4.
Answer:
(x+2) (x+3) (x-5)
Step-by-step explanation:
x³-19x-30 = (x+2) (x²+ax-15) ... x³=x*(1*x²) while -30= (2)*(-15)
x³ +<u> 0</u>*x² - 19x -30 = x³ + (<u>2+a</u>)x² + (2a-15)x -30
2+a = 0
a = -2
x³-19x-30 = (x+2) (x²-2x-15) = (x+2) (x+3) (x-5)
(-2,-2)
Since it has a negative in front of the absolute value, the graph is a downward cone.
The answer is 16 if you solve it, because the square root of 64 is 8 and 2 * 8 = 16
