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Ilia_Sergeevich [38]
4 years ago
8

The weight of the space shuttle is about 4.5 million pounds. How many people would it take to move it? Answer in units of people

.
Physics
1 answer:
larisa [96]4 years ago
7 0

Assuming that they are pulling the space shuttle straight up, and that this is done on the surface of the earth, where gravity is equal to 9.8 m/s^2. So taking the average pull force of a person to be 110 kg, then: <span>

110 kg/person * 9.8 m/s^2 = 1078 kg*m/s^2, or 1078 N/person (Newtons). </span>

1 Newton is about 0.225 lb. So, 1078 N/person * 0.225 lb/N = 242.34 lb/person. <span>

So if the space shuttle weighs 4,500,000 lb, then it would take 4,500,000 lb / (242.34 lb/person) = 18,569 people. </span>

 

Answer:

<span>18,569 people</span>

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Martin has severe myopia, with a far point on only 17 cm. He wants to get glasses that he'll wear while using his computer whose
marusya05 [52]

Answer:

Explanation:

Far point = 17 cm . That means he can not see beyond this distance .

He wants to see at an object at 65 cm away . That means object placed at 65 has image at 17 cm by concave lens . Using lens formula

1 / v - 1 / u = 1 / f

1 / - 17 - 1 / - 65 = 1 / f

= 1 / 65 - 1 / 17

= -  .0434 = 1 / f

power = - 100 / f

= - 100 x .0434

= - 4.34 D .

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4 years ago
A family drives north for 30km then turns east for 20km. The family then decided to turn west for 5km before finally stopping to
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Answer:

A

Explanation:

They drove 30km north. The displacement adds up to 25km therefore making the distance greater

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A baseball of mass m = 0.31 kg is spun vertically on a massless string of length L = 0.51m. The string can only support a tensio
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Given data:

* The mass of the baseball is 0.31 kg.

* The length of the string is 0.51 m.

* The maximum tension in the string is 7.5 N.

Solution:

The centripetal force acting on the ball at the top of the loop is,

\begin{gathered} T+mg=\frac{mv^2}{L}_{} \\ v^2=\frac{L(T+mg)}{m} \\ v=\sqrt[]{\frac{L(T+mg)}{m}} \end{gathered}

For the maximum velocity of the ball at the top of the vertical circular motion,

v_{\max }=\sqrt[]{\frac{L(T_{\max }+mg)}{m}}

where g is the acceleration due to gravity,

Substituting the known values,

\begin{gathered} v_{\max }=\sqrt[]{\frac{0.51(7.5_{}+0.31\times9.8)}{0.31}} \\ v_{\max }=\sqrt[]{\frac{0.51(10.538)}{0.31}} \\ v_{\max }=\sqrt[]{17.34} \\ v_{\max }=4.16\text{ m/s} \end{gathered}

Thus, the maximum speed of the ball at the top of the vertical circular motion is 4.16 meters per second.

8 0
1 year ago
What factors can cause an induced current in a wire loop through which a magnetic field passes?.
sp2606 [1]

The factors that  can cause an induced current in a wire loop are number of turns of the wire, area of the wire and magnetic field strength.

<h3>Induced emf</h3>

According to Faraday's law of electromagnetic induction, the rate of change of flux in a magnetic field is proportional to the flux through the magnetic field.

emf = dФ/dt

where;

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emf = N(BA)/dt

where;

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Thus, the factors that  can cause an induced current in a wire loop are number of turns of the wire, area of the wire and magnetic field strength.

Learn more about electromagnetic induction here: brainly.com/question/26334813

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