Answer:
Momentum of the bowling pin is 17kgm/s
Explanation:
P(initial of ball)=+30 kg m/s
P(initial of pin)=0 because its velocity is 0
P initial = P final
30= P(ball) + P(pin)
30=13+P(pin)
P(final of pin)=+13 kg m/s and P(final of ball)= 30-13=17kgm/s
Answer:
0.39 km west
Explanation:
The position of Runner A is:
x = -5.7 + 8.8 t
The position of Runner B is:
x = 4.2 − 7.6 t
When the positions are equal:
-5.7 + 8.8 t = 4.2 − 7.6 t
16.4 t = 9.9
t = 0.604
Plug into either equation to find the position at this time:
x = -5.7 + 8.8 (0.604)
x = -0.39
The runners are 0.39 km west of the flagpole when they meet.
Explanation:
The newton (symbol: N) is the International System of Units (SI) derived unit of force.
This causes reverse faults<span>, which are the reverse of </span>normal faults<span>, because in this case, the hanging wall slides upward relative to the footwall. Shear </span>stress<span> is when rock slabs slide past each other horizontally. There is no vertical movement of either the hanging wall or footwall, and we get a strike-slip </span>fault<span>.</span>
Answer:
(a) the high of a hill that car can coast up (engine disengaged) if work done by friction is negligible and its initial speed is 110 km/h is 47.6 m
(b) thermal energy was generated by friction is 1.88 x
J
(C) the average force of friction if the hill has a slope 2.5º above the horizontal is 373 N
Explanation:
given information:
m = 750 kg
initial velocity,
= 110 km/h = 110 x 1000/3600 = 30.6 m/s
initial height,
= 22 m
slope, θ = 2.5°
(a) How high a hill can a car coast up (engine disengaged) if work done by friction is negligible and its initial speed is 110 km/h?
according to conservation-energy
EP = EK
mgh = 
gh = 
h = 
= 47.6 m
(b) If, in actuality, a 750-kg car with an initial speed of 110 km/h is observed to coast up a hill to a height 22.0 m above its starting point, how much thermal energy was generated by friction?
thermal energy = mgΔh
= mg (h -
)
= 750 x 9.8 x (47.6 - 22)
= 188160 Joule
= 1.88 x
J
(c) What is the average force of friction if the hill has a slope 2.5º above the horizontal?
f d = mgΔh
f = mgΔh / d,
where h = d sin θ, d = h/sinθ
therefore
f = (mgΔh) / (h/sinθ)
= 1.88 x
/(22/sin 2.5°)
= 373 N