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jonny [76]
3 years ago
8

HELP ASAP PLEASE - Which best describes how the arrangement of the sun, moon, and the earth affect the range of the tides during

a spring tide?
A. Because the earth, moon, and sun are all out of alignment, the pull of the moon and sun act in the opposite direction causing the highest high tides and the lowest low tides.


B. Because the earth, moon, and sun are in alignment, the pull of the moon and sun act in the same direction, causing the highest high tides and the lowest low tides.


C. Because the earth, moon, and sun are all out of alignment, the pull of the moon and sun act in the opposite direction, causing the lowest high tides and the highest low tides.


D. Because the earth, moon, and sun are all in alignment, the pull of the moon and sun act in the same direction causing the lowest high tides and the highest low tides.
Physics
2 answers:
koban [17]3 years ago
3 0
B. When the sun and the moon are aligned, their combined gravitational force attracts the water, causing super high tides on one side of the planet, and super low tides on the opposite side.
Simora [160]3 years ago
3 0

Answer: B. Because the earth, moon, and sun are in alignment, the pull of the moon and sun act in the same direction, causing the highest high tides and the lowest low tides.

Explanation:

The rise in level of waves due to gravitational pull of the sun and the moon are tides. Spring tides occur during new moon or full moon when the Sun, the Moon and The Earth all align in one straight line. The strong gravitational pull causes the highest high tides and the lowest low tides. Thus, the correct option is B.

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Answer:

(a) t = 22.9 s

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The uniformly accelerated circular movement, is a circular path movement in which the angular acceleration is constant.

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ωf ²=  ω₀² + 2*α*θ  Formula (1)

ωf= ω₀ + α*t Formula (2)

Where:

θ : angle that the body has rotated in a given time interval (rad)

α : angular acceleration (rad/s²)

t : time interval (s)

ω₀ : initial angular speed ( rad/s)

ωf : final angular speed ( rad/s)

Data

θ =  19.5 revolutions  : angular displacement of each wheel or angle that the  wheel has rotated in a given time interval

ω₀= 10.7 rad/s :  initial angular speed of the Wheel ( rad/s)

ωf = 0 : final angular speed  of the Whee( rad/s)

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We replace data in the fómula (1),considering that 1 revolution is equal to 2π radians :

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