1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jonny [76]
2 years ago
8

HELP ASAP PLEASE - Which best describes how the arrangement of the sun, moon, and the earth affect the range of the tides during

a spring tide?
A. Because the earth, moon, and sun are all out of alignment, the pull of the moon and sun act in the opposite direction causing the highest high tides and the lowest low tides.


B. Because the earth, moon, and sun are in alignment, the pull of the moon and sun act in the same direction, causing the highest high tides and the lowest low tides.


C. Because the earth, moon, and sun are all out of alignment, the pull of the moon and sun act in the opposite direction, causing the lowest high tides and the highest low tides.


D. Because the earth, moon, and sun are all in alignment, the pull of the moon and sun act in the same direction causing the lowest high tides and the highest low tides.
Physics
2 answers:
koban [17]2 years ago
3 0
B. When the sun and the moon are aligned, their combined gravitational force attracts the water, causing super high tides on one side of the planet, and super low tides on the opposite side.
Simora [160]2 years ago
3 0

Answer: B. Because the earth, moon, and sun are in alignment, the pull of the moon and sun act in the same direction, causing the highest high tides and the lowest low tides.

Explanation:

The rise in level of waves due to gravitational pull of the sun and the moon are tides. Spring tides occur during new moon or full moon when the Sun, the Moon and The Earth all align in one straight line. The strong gravitational pull causes the highest high tides and the lowest low tides. Thus, the correct option is B.

You might be interested in
(a) The Sun orbits the Milky Way galaxy once each 2.60 x 108y , with a roughly circular orbit averaging 3.00 x 104 light years i
PilotLPTM [1.2K]

Answer:

Part a)

a_c = 1.67 \times 10^{-10} m/s^2

Part b)

v = 2.18 \times 10^5 m/s

Explanation:

Time period of sun is given as

T = 2.60 \times 10^8 years

T = 2.60 \times 10^8 (365 \times 24 \times 3600) s

T = 8.2 \times 10^{15} s

Now the radius of the orbit of sun is given as

R = 3.00 \times 10^4 Ly

R = 3.00 \times 10^4 (3\times 10^8)(365 \times 24 \times 3600)m

R = 2.84 \times 10^20 m

Part a)

centripetal acceleration is given as

a_c = \omega^2 R

a_c = \frac{4\pi^2}{T^2} R

a_c = \frac{4\pi^2}{(8.2\times 10^{15})^2}(2.84 \times 10^{20})

a_c = 1.67 \times 10^{-10} m/s^2

Part b)

orbital speed is given as

v = \frac{2\pi R}{T}

v = \frac{2\pi (2.84 \times 10^{20})}{8.2 \times 10^{15}}

v = 2.18 \times 10^5 m/s

5 0
3 years ago
Which is an example of convection
Brums [2.3K]
Heating A Pot Filled With Water
4 0
3 years ago
Read 2 more answers
An electric car is being designed to have an average power output of 4,600 W for 2 h before needing to be recharged. (Assume the
MAVERICK [17]

Answer:

a)3312 x 10⁴ J

b)I = 57.5 A

c)9200 W

Explanation:

Given that

P =4600 W

Time t= 2 h = 2 x 3600 s= 7200 s

We know that

1 W = 1 J/s

a)

Energy stored in the battery = P .t

                                              =4600 x 7200 J

                                            =3312 x 10⁴ J

b)

We know that power P given as

P = V .I

V=Voltage  ,I =Current

4600 = 80 x I

I = 57.5 A

c)

The energy supplied = 4600 x 2 = 9200 W

7 0
3 years ago
A 40-kg box is being pushed along a horizontal smooth surface. The pushing force is 15 n directed at an angle of 15° below the
Kobotan [32]

Answer:

Acceleration of the crate is 0.362 m/s^2.

Explanation:

Given:

Mass of the box, m = 40 kg

Applied force, F = 15 N

Angle at which the force is applied, (\theta) = 15°

We have to find the magnitude of the acceleration.

Let the acceleration be "a".

FBD is attached with where we can see the horizontal and vertical component of force.

⇒ F_x=Fcos(\theta)          and             ⇒ F_y=Fsin (\theta)

⇒ F_x=15cos(15)                           ⇒ F_y=15sin (15)

⇒ Applying concept of  forces.

⇒ \sum F_x=F_n_e_t =F-f

⇒ F_n_e_t =F-f

⇒ ma =F-f       <em>  ...Newtons second law Fnet = ma</em>

⇒ a =\frac{F-f}{m}              

⇒ Plugging the values.

⇒ a =\frac{15cos(15)-0}{40}     <em>...f is the friction which is zero here.</em>

⇒ a =\frac{14.48}{40}

⇒ a=0.362\ ms^-^2

Magnitude of the acceleration of the crate is 0.362 m/s^2.

4 0
3 years ago
_____ occurs when light changes direction after colliding with particles of matter
KengaRu [80]
Scattering occurs when light changes direction after colliding with particles of matter.
4 0
2 years ago
Other questions:
  • True or False? <br> Metrics are based on the British system of weights and measures.
    6·2 answers
  • Jupiter is composed almost entirely of gases and liquids, mostly
    6·2 answers
  • Air at 38oC and 97% relative humidity is to be cooled to 14oC and fed into a plant area at a rate of 510 m3/min. Calculate the r
    6·1 answer
  • What is the speed vf of the package when it hits the ground?
    7·1 answer
  • When you go "down" the food chain by continuing to ask "what does it eat?" at what category of living things do you always end u
    12·1 answer
  • N discussing engines, the ratio of output work to input work expressed as a percentage is called
    11·1 answer
  • An electron with a speed of 0.95c is emitted by a supernova, where cc is the speed of light. What is the magnitude of the moment
    9·1 answer
  • How do quantum numbers relate to electrons?<br> please explain?
    6·1 answer
  • Match the microscopes with their useable
    7·2 answers
  • Predict the magnitude of the gravitational force....
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!