1 is in the 'Ten Thousand's' place.
Answer:
no
Step-by-step explanation:
We want to compare the pot holder hole dimension to the pot dimension. The hole diameter is the overall pot holder diameter less the wall thickness on either side:
hole diameter = (20 1/5) -2(1 2/7) = 20 -2(1) +1/5 -(2)(2/7)
= 18 +(1/5 -4/7) = 18 +(7 -20)/35 = 18 -13/35
= 17 22/35 . . . . cm
We want to compare this to 17 4/5. We can do that by using a common denominator for the fractions.
17 4/5 = 17 + (4/5)(7/7) = 17 28/35 . . . . cm
The pot has a diameter of 17 28/35 cm; the pot holder has a hole diameter of 17 22/35 cm, so <em>the hole is smaller than the pot</em>.
The pot will not fit into the plant pot holder.
_____
You can use your calculator to find the free space around the pot by computing ...
20 1/5 -2(1 2/7) -17 4/5 = free space = -6/35 . . . . cm
Negative space means the pot is larger than the hole.
Answer:
9y-24
Step-by-step explanation:
3(y-8)+3(2y)
3y-24+6y
9y-24
Answer: A) 18.2 minutes
B) 4.5 minutes.
Step-by-step explanation:
A) Maxine can mow one lawn in 24 minutes, so the rate of work is:
1/24 of the lawn per minute.
Sammie can mow one lanw in 36 minutes, so the rate of work is:
1/36 of the lawn per minute.
The amount of the lawn that each has left to lawn by the minute x is:
Maxine = 1 -(1/24)*x
Sammie = 1 - (1/36)*x
we want to find the value of x such that:
2*(1 - (1/24)*x) = 1 - *(1/36)*x
which means that the amount that Sammie has left is two times the amount that Maxine has left to mow.
2 - (1/12)*x = 1 - (1/36)*x
2 - 1 = (1/12 - 1/36)*x
1/0.055 = x = 18.2
by the minute 18.2
B) Similar to before, here the rates are:
For Maxine, R = 1/6
For Sammie, R = 1/9
The amount they have left to mow by minute x is:
Maxine = 1 - (1/6)*x
Sammie = 1 - (1/9)*x
We want to solve, similar to before.
2( 1 - (1/6)*x) = 1 - (1/9)*x
2 - (1/3)*x = 1 - (1/9)*x
2 - 1 = (1/3 - 1/9)*x
1 = (2/9)*x
1*9/2 = x = 4.5
So here the solution is 4.5 minutes. Hope this helps