Write the equation and identify the slope, y-intercept, an

Is -0.78 greater or less than -5/6

Natali5045456 [20]

Answer:

$-0.78 > -\dfrac{5}6 ~~ \text{or}~~-0.78> -0.8\overline 3$

Step-by-step explanation:

5 0

3 years ago

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The graph of F(x) can be compressed vertically and shifted to the right to produce the graph of G(x) . If F(x) = x ^ 3 , which o

meriva

Given:

The function is:

$F(x)=x^3$

To find:

The function G(x) if the graph of F(x) can be compressed vertically and shifted to the right to produce the graph of G(x).

Solution:

The transformation is defined as

$g(x)=kf(x+a)+b$ .... (i)

Where, k is stretch factor, a is horizontal shift and b is vertical shift.

If 0<k<1, then the graph compressed vertically by factor k and if k>1, then the graph stretch vertically by factor k.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

It is given that F(x) can be compressed vertically and shifted to the right to produce the graph of G(x). So, the value of k must be lies between 0 and 1, and a<0.

In option A, $0$ and $a$ . So, this option is correct.

In option B, $0$ and $a>0$ . So, this option is incorrect.

In option C, $k>1$ and $a>0$ . So, this option is incorrect.

In option D, $k>1$ and $a$ . So, this option is incorrect.

Therefore, the correct option is A.

3 0

3 years ago

Which of the following represents the zeros of f(x) = 5x3 − 6x2 − 59x + 12? (2 points)

Furkat [3]

Answer:

4, −3, 1 over 5

Step-by-step explanation:

x is a zero of $f(x)$ if $f(x) = 0$

In this problem, we have that:

$f(x) = 5x^{3} - 6x^{2} - 59x + 12$

4, 3, 1 over 5

$f(4) = 5*4^{3} - 6*4^{2} - 59*4 + 12 = 0$

So 4 is a zero of the function

$f(3) = 5*3^{3} - 6*3^{2} - 59*3 + 12 = -84$

So 3 is not a zero of the function, and this option is incorrect

4, 3, − 1 over 5

$f(3) = 5*3^{3} - 6*3^{2} - 59*3 + 12 = -84$

So 3 is not a zero of the function, and this option is incorrect

4, −3, 1 over 5

$f(4) = 5*4^{3} - 6*4^{2} - 59*4 + 12 = 0$

So 4 is a zero of the function

$f(-3) = 5*(-3)^{3} - 6*(-3)^{2} - 59*(-3) + 12 = 0$

So -3 is a zero of the function

$f(\frac{1}{5}) = f(0.2) = 5*(0.2)^{3} - 6*(0.2)^{2} - 59*(0.2) + 12 = 0$

So 1 over 5 is a zero of the function

This is the correct answer.

4, −3, −1 over 5

$f(4) = 5*4^{3} - 6*4^{2} - 59*4 + 12 = 0$

So 4 is a zero of the function

$f(-3) = 5*(-3)^{3} - 6*(-3)^{2} - 59*(-3) + 12 = 0$

So -3 is a zero of the function

$f(-\frac{1}{5}) = f(-0.2) = 5*(-0.2)^{3} - 6*(-0.2)^{2} - 59*(-0.2) + 12 = 23.52$

-1 over 5 is not a zero of the function

5 0

3 years ago

How to solve this it says solve 6!

Dennis_Churaev [7]

Answer:

720

Step-by-step explanation:

6*5*4*3*2*1=720

8 0

3 years ago

I need to know what to do for this problem. I am confused. Thanks♡

steposvetlana [31]

$1,154 will be what each kid needs to raise, you must add up both travel expenses, which totals $10,386, and divide that with the number of children (9), and you get your answer:)! hope this helps.

6 0

3 years ago

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