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4 years ago

Which part of an atom is actively exchanged or shared in a chemical bond? proton neutron electron all of the above

Mathematics

2 answers:

lapo4ka [179]4 years ago

7 0

C.) "Electrons" is actively exchanged or shared in a chemical bond

Hope this helps!

Olegator [25]4 years ago

5 0

The answer is the proton

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Find the approximate area of a triangle that has vertices at A(-4,2),B(6,4)C(3,-1)

MrMuchimi

$area \: of \: triangle \: = \frac{1}{2} |( - 16) - (22)|$
$= \frac{1}{2} | - 44|$
$= | - 22|$
$area \: of \: triangle \: = 22$

6 0

3 years ago

Find all real zeros of 4x^3-20x+16

Pani-rosa [81]

Answer:

{1, (-1±√17)/2}

Step-by-step explanation:

There are formulas for the real and/or complex roots of a cubic, but they are so complicated that they are rarely used. Instead, various other strategies are employed. My favorite is the simplest--let a graphing calculator show you the zeros.

___

Descartes observed that the sign changes in the coefficients can tell you the number of real roots. This expression has two sign changes (+-+), so has 0 or 2 positive real roots. If the odd-degree terms have their signs changed, there is only one sign change (-++), so one negative real root.

It can also be informative to add the coefficients in both cases--as is, and with the odd-degree term signs changed. Here, the sum is zero in the first case, so we know immediately that x=1 is a zero of the expression. That is sufficient to help us reduce the problem to finding the zeros of the remaining quadratic factor.

Using synthetic division (or polynomial long division) to factor out x-1 (after removing the common factor of 4), we find the remaining quadratic factor to be x²+x-4.

The zeros of this quadratic factor can be found using the quadratic formula:

a=1, b=1, c=-4

x = (-b±√(b²-4ac))/(2a) = (-1±√1+16)/2

x = (-1 ±√17)2

The zeros are 1 and (-1±√17)/2.

_____

The graph shows the zeros of the expression. It also shows the quadratic after dividing out the factor (x-1). The vertex of that quadratic can be used to find the remaining solutions exactly: -0.5 ± √4.25.

The given expression factors as ...

4(x -1)(x² +x -4)

5 0

3 years ago

Read 2 more answers

Find two consecutive odd integers whose sum is 116 (and please have steps) thank you

matrenka [14]

It's 57 and 59
Call (n) is the first odd interger => the second odd interger is (n+2)
=> n + (n + 2) = 116
=> n + n + 2 = 116
=> 2n = 114
=> n = 57
First odd interger is 57 and the second odd interger is 59 .
Sorry my English so bad =)))

6 0

3 years ago

Vectors! Please help! This is the last question OF MY WHOLE SEMESTER! I've tried it so many times and can't get it right. :(

Feliz [49]

Pictures always help; see the one I've attached for reference.

Call the first vector (from HQ to the supply drop) u and the second vector (from supply drop to medics) v. We then want to find w, the vector from the medics to HQ, which corresponds to the vector -(u + v). (This is because u + v is the vector pointing from HQ to the medics; we're talking about the one in the opposite direction.)

Write the vectors in horizontal/vertical component form:

u = (125 km) (cos 235º x + sin 235º y) = (-71.70 x - 102.39 y) km

v = (75 km) (cos 110º x + sin 110º y) = (-25.65 x + 70.48 y) km

Why these angles?

"55 degrees south of west" is 235º; due west is 180º from the positive horizontal axis, and you add 55º to this
"20 degrees west of north" is 110º; due north is 90º, so add 20º to this

Add the vectors:

u + v = (-97.35 x - 31.92 y) km

Multiply by -1 to get the vector w:

w = -(u + v) = (97.35 x + 31.92 y) km

The distance covered by this vector is equal to its magnitude:

||w|| = √((97.35 km)^2 + (31.92 km)^2) = 102.45 km

The direction θ is given by

tanθ = (31.92 km)/(97.35 km) ==> θ = 18.15º