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3 years ago

14

I have 15a but I need 15b and 14

1 answer:

Naily [24]3 years ago

8 0

14. For a prism, the volume is given by
.. V = Bh . . . . . . . . where B is the area of the base, and h is the height of the prism

For a pyramid, the volume is given by
.. V = (1/3)*Bh . . . . where B is the area of the base, and h is the height of the pyramid

The volume is proportional to the area of the base. If the dimensions of the base decrease linearly to zero at the height of the geometry as they do for pyramids and cones, then the volume formula includes a factor of 1/3.

15b. The volume of a pyramid is 1/3 that of a prism with the same base area and height.

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Find the nth term in the sequence <br> -6,-3,0,3,6

RoseWind [281]

First, determine what type of sequence the set of numbers make up. Through simple logic, it is an arithmetic sequence, because one can see by inspection that there is a common difference of 3 (positive 3, just to be a bit more pedantic).

We then use the formula, $t_{n} = a + (n - 1)d$
where $t_{n}$ represents the $n^{th}$ term; a represents the starting term (so the first number in the set of numbers, which in this case is -6); n is the term number (1st, 2nd, 3rd term, etc.); d is the common difference, that is, when you subtract the next term to the previous term – what is that numerical value.

To elaborate a bit more, your 1st term is -6, 2nd is -3, 3rd is 0, etc.

Also, the formula above is something you just learn, unless you learn to proof this formula, which is something different.

So, here, $t_{n} = -6 + (n-1)3$ , which can be expanded to:
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6 0

3 years ago

Read 2 more answers

A shipping pallet holds 10 boxes. Each box holds 300 parts of different

vfiekz [6]

Answer:

(a) The mean and standard deviation of the pallet weight are 3000 lb and 10.95 lb respectively.

(b) The probability that the pallet weight (W) will exceed 3015 lb is 0.085.

Step-by-step explanation:

Let the random variable <em>X</em> denote the weight of the parts.

The random variable <em>X</em> is normally distributed with parameters, <em>μ</em> = 1 lb and <em>σ</em> = 0.20 lb.

It is provided that a shipping pallet holds 10 boxes and each box holds 300 parts of different types.

That is, there are a total of 300 × 10 = 3000 parts in a pallet.

(a)

Compute the mean and standard deviation of the pallet weight as follows:

Mean of the pallet weight = n × E (X)

$=n\times\mu\\\\=3000\times 1\\\\=3000$

Standard deviation of the pallet weight = $\sqrt{3000\times V(X)}$

$=\sqrt{3000\times (0.20)^{2}}\\\\=\sqrt{120}\\\\=10.9544512\\\\\approx10.95$

Thus, the mean and standard deviation of the pallet weight are 3000 lb and 10.95 lb respectively.

(b)

Compute the probability that the pallet weight (W) will exceed 3015 lb as follows:

$P(W>3015)=P(\frac{W-\mu}{\sigma}>\frac{3015-3000}{10.95})$

$=P(Z>1.37)\\\\=1-P(Z$

*Use a <em>z</em>-table.

Thus, the probability that the pallet weight (W) will exceed 3015 lb is 0.085.

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3 years ago

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Answer:

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3 years ago

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Setler79 [48]

A 3 1/2 feet

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4 years ago