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3 years ago

I have 15a but I need 15b and 14

Mathematics

1 answer:

Naily [24]3 years ago

8 0

14. For a prism, the volume is given by
.. V = Bh . . . . . . . . where B is the area of the base, and h is the height of the prism

For a pyramid, the volume is given by
.. V = (1/3)*Bh . . . . where B is the area of the base, and h is the height of the pyramid

The volume is proportional to the area of the base. If the dimensions of the base decrease linearly to zero at the height of the geometry as they do for pyramids and cones, then the volume formula includes a factor of 1/3.

15b. The volume of a pyramid is 1/3 that of a prism with the same base area and height.

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Write an equation for the following and then solve.<br> Twice a number is 8. Find the number.

Yakvenalex [24]

Answer:

The number u are looking for is 4

Step-by-step explanation:

Let X be the unknown number that we want to find.

So it becomes,

2X = 8

move 2 to the other side, so it becomes a divide

X = 8/2

X = 4

6 0

2 years ago

4. Tristan has a total of 30 dimes & nickels. The total value

adelina 88 [10]

Answer:

x/2 + x = 30 -> $2.50

20/2 + 20 = 30

X = 20, therefore:

dimes = 20

nickels = 10

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2 years ago

Read 2 more answers

What is the probability of rolling a four then a three

spayn [35]

Answer:

$\frac{1}{36}$

Step-by-step explanation:

Total possibilities when we a roll a die at a time are 6

given we should have four for first time and then three

let us assume we rolled the dice we may get 1,2,3,4,5,6(any of these) the probability to get 4 is

PROBABILITY= $\frac{\textrm{FAVOURABLE CHANCES}}{\textrm{TOTAL CHANCES}}$

Favourable chances=1

Total chances=6

Probability= $\frac{1}{6}$

the prabability to get 4 in first roll is $\frac{1}{6}$ .

let us assume we rolled the dice for second time again we may get 1,2,3,4,5,6(any of these) the probability to get 3 is

Favourable chances=1

total chances=6

probability= $\frac{1}{6}$

the probability to get 3 in second roll irrespective of first one is $\frac{1}{6}$

the probability to get 4 in first time and then 3 is

The probability to occur both events at a time is multiplication of individual probabilities

So,

probablility to get 4 in first roll= $\frac{1}{6}$

probability to get 3 in second roll= $\frac{1}{6}$

probability to occur both at a same time is = $\frac{1}{6}$ $\times$ $\frac{1}{6}$ = $\frac{1}{36}$

6 0

2 years ago

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Slav-nsk [51]

Nice hfiebeiciysbwjwkdkcoc

7 0

3 years ago

lukranit [14]

Answer:

12.56

Step-by-step explanation:

180/360×2×3.142×4

4 0

2 years ago