HELP! Please! Answers, A256 in2 b443.4 in2 c512 in2 d362 in2

Sos HELP MEEEEE I HAVE NO CLUE PLZ EXPLAIN !!!

OleMash [197]

2,376 square feet
**
Add the areas of all the sides of the shape.
A triangle's area: 1/2bh
The two triangles' area=24*9=216
The bottom side: 40*24=960
The two other sides: 30*40=1200
Add everything: 216+960+1200=2376

5 0

4 years ago

Ahmed paid $18 for a shirt which has a marked price of $25. What is the percentage discount?

Alina [70]

18/25=0.72
1-0.72=0.28 or 28%

5 0

3 years ago

- Will mark brainliest.

Nostrana [21]

I hope that my answer is 100 percent correct I think the answer is b

3 0

3 years ago

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The area of the regular hexagon is 169.74 ft2 what is the perimeter, rounded to the nearest tenth

Bess [88]

Answer:

Perimeter of given regular hexagon is 48.5 ft.

Step-by-step explanation:

Let ABCDEF be the regular hexagon as shown in the attached figure.

O be the intersection point of the diagonals EB, FC and AD.

As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.

In other words,

$\triangle EOD, \triangle DOC, \triangle BOC, \triangle AOB, \triangle AOF , \triangle FOE$ are equilateral $\triangle s$ .

Area of an equilateral $\triangle$ is defined as :

$\dfrac{\sqrt{3}}{4} \times a^{2}$

Where a is the side of $\triangle$ .

Area of hexagon = $6 \times \dfrac{\sqrt{3}}{4}\times a^{2}$

We are given that area of hexagon = 169.74 $ft^{2}$

Let s be the side of hexagon.

$\Rightarrow 6 \times \dfrac{\sqrt{3}}{4}s^{2} = 169.74 ft^{2}\\\Rightarrow s = 8.08 ft$

A regular Hexagon is made up of 6 equal sides, so

Perimeter of a regular hexagon = $6 \times side$

Perimeter = $6 \times 8.08$

$\Rightarrow 48.5 ft$

So, perimeter of given regular hexagon is $48.5 ft$ .

6 0

3 years ago

Help please, will mark brainliest!

inysia [295]

Answer:

A is your answer

Step-by-step explanation: B is wrong because if it was -6 then it would equal -216

7 0

3 years ago

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