How do I solve this equation by taking the square root?

An angle measured 10 degrees less than the measure of its complementary angle. Find the measure of both angles

Mazyrski [523]

Answer:

The measure of the angles are 40 degrees and 50 degrees

Step-by-step explanation:

Let

x ----> the measure of one angle in degrees

y ----> the measure of the complementary angle in degrees

we know that

If two angles are complementary, then their sum is equal to 90 degrees

so

$x+y=90$ ----> equation A

we have that

$x=y-10$ ----> equation B

Substitute equation B in equation A and solve for y

$(y-10)+y=90\\2y-10=90\\2y=100\\y=50$

Find the value of x

$x=50-10=40$

therefore

The measure of the angles are 40 degrees and 50 degrees

3 0

2 years ago

Please help! An archway will be constructed over a walkway. A piece of wood will need to be curved to match a parabola. Explain

Gwar [14]

draw a perpendicular line from the directrix passing through the focus, this will be the line of symmetry. The vertex(h, k) will be located on the line half way between the focus and directrix. The distance from the focus to the vertex is called the focal length, call it a. The then equation is (x - h)^2 = 4a(y - k) the equation can be manipulated to y = 1/4a(x - h)^2 + k hope it helps

6 0

3 years ago

Read 2 more answers

What is the equation, in standard form, of a parabola that models the values in the table?

love history [14]

Answer:

$Y=4x^2+3x-6$

Step-by-step explanation:

For the standard form equation to model the values in the table, each value of x in the table should give the matching the y value when substituted into the equation. We will test each equation:

$Y=3x^2+4x-6$ for (-2,4)

$Y=3(-2)^2+4(-2)-6=3(4)+-8-6=12+-8-6=-2\\$

This does not give 4 as the answer and is not a solution.

$Y=4x^2+3x-6$ for (-2,4)

$Y=4(-2)^2+3(-2)-6=4(4)+-6-6=16+-6-6=-4\\$

This does give 4 as the answer and is a possible solution.

$Y=4x^2-3x-6$ for (-2,4)

$Y=4(-2)^2-3(-2)-6=4(4)+6-6=16+6-6=16\\$

This does not give 4 as the answer and is not a solution.

$Y=-4x^2-3x-6$ for (-2,4)

$Y=-4(-2)^2-3(-2)-6=-4(4)+6-6=-16+6-6=-16\\$

This does not give 4 as the answer and is not a solution.

The only possible solution is $Y=4x^2+3x-6$

3 0

3 years ago

PLEASE HELP SOON. i have been stuck on this algebra 1 question for what feels like an eternity can someone please help and soon?

-Dominant- [34]

You are trying to find an x-value for which f(x) = g(x). At first your choice of x is arbitrary. In the given table, the first x-value tried was 0 (zero). For this value of x, f(x) does NOT equal g(x).

Next x was 1. f(x) and g(x) are even further apart here. So reject 1 and try 2 instead. Notice how f(x) and g(x) are closer together now than they were for x=1.

Note that for x=2.5, f(x) and g(x) are even closer together; ony 0.75 separates them.

Your turn. Try x=2.4, x=2.3, and so on. You may have to go in the other direction: Try x=2.6, x=2.7, and so on. If f(x) and g(x) are getting closer to one another, you're going in the right direction; if further apart, you're going in the wrong direction.

Have fun. This really is an interesting problem.

6 0

2 years ago

Explain how you can use base-ten blocks or as a decimal models to find 3.15 divided by 3. Include pictures to support your expla

blondinia [14]

With base-ten blocks ,there would be the 3 units, 1 tens block , and five hundreds cubes

3 0

2 years ago