All categories

3 years ago

TELL ME IF U HAVE TO MULTIPLY OR DIVED THATS IT

Mathematics

1 answer:

docker41 [41]3 years ago

8 0

1.Multiply 2.Divide 3.Multiply 4.Divide 5.Divide (I think these are right)

You might be interested in

Help pleaseeeee??????????????

ArbitrLikvidat [17]

Answer:

4x-1 is the correct answer

Step-by-step explanation:

Please mark brainliest

5 0

3 years ago

I’ll give you brainliest for the first person with an answer

raketka [301]

Answer:

1296mm^2

Step-by-step explanation:

Surface Area of the Rectangular Prism to the left on top of the box:

Area of square = lw, 9mm * 9mm = 81mm, then multiply by 2 because 2 of the squares are a part of the surface, giving 162mm^2

Area of a rectangle =lw, 9mm * 9mm = 81mm, then multiply by 2 again, because 2 rectangles are a part of the surface, giving 162mm^2

So, the total surface area of the rectangular prism to the left on top, is 324mm^2

Surface Area of the Triangular Prism:

Area of a triangle: 1/2bh, and our base length would be 12, because we have to subtract 9 from 21 since the base length of the triangle isn't stated. Anyways, A = 1/2bh, so A = 1/2(12)(9) = 54mm^2, but multiply by two, so we get 108mm^2.

Area of the rectangle: lw, so 15mm * 9mm = 135mm^2

So, the total surface area of the triangular prism is 243mm^2

Surface Area of the Rectangular Prism at the bottom:

Area of the long rectangles in front = lw, 21mm * 9mm = 189mm^2, multiply by 2, 378mm^2

Area of the rectangles to the side = lw, 9mm * 9mm = 81mm^2, multiply by 2, 162mm^2

Area of the rectangle at the very bottom = lw, 21mm * 9mm = 189mm^2

So, the total surface area of the rectangular prism at the bottom is 729mm^2

Add all the total surface areas of each shape to get the total surface area of the figure:

324mm^2 + 243mm^2 + 729mm^2 = 1296mm^2

The surface area of the figure above is 1296mm^2

4 0

2 years ago

Find the exact value of the trigonometric expression given that sin(u) = -(3/5),

GuDViN [60]

Recall that

$\cot(u+v)=\dfrac{\cos(u+v)}{\sin(u+v)}=\dfrac{\cos u\cos v-\sin u\sin v}{\sin u\cos v+\cos u\sin v}=\dfrac{\cot u\cot v-1}{\cot v+\cot u}$

Also, recall that for all $\theta$ ,

$\cos^2\theta+\sin^2\theta=1$

With $\frac{3\pi}2$ , we can expect $\cos u>0$ , and with $0$ , $\sin v>0$ . So from the above identity it follows that

$\cos u=\sqrt{1-\sin^2u}=\dfrac45\implies\cot u=\dfrac{\cos u}{\sin u}=-\dfrac43$

and

$\sin v=\sqrt{1-\cos^2v}=\dfrac8{17}\implies\cot v=\dfrac{\cos v}{\sin v}=\dfrac{15}8$

and so

$\cot(u+v)=\dfrac{-\frac43\frac{15}8-1}{\frac{15}8-\frac43}=\boxed{-\dfrac{84}{13}}$

6 0

3 years ago

Please write it down step by step :)

grandymaker [24]

Answer:

-6

Step-by-step explanation:

Some nasty order of operations coming up.

Firstly, deal with that squared:

-12 / 3 * (-8 + 16 - 6) + 2

Simplify the bracket:

-12 / 3 * 2 + 2

Simplify -12 / 3:

-4 * 2 + 2

Simplify -4 * 2:

-8 + 2

Simplify:

-6

3 0

3 years ago

I need help! Please?

joja [24]

Answer:

Its a

Step-by-step explanation:

Just divide any one of the cost with the pounds. Ex. 20.72/8=2.59

4 0

3 years ago

Read 2 more answers