Set up a system of equations.
0.10d + 0.25q = 39.25
d + q = 250
Where 'd' represents the number of dimes, and 'q' represents the number of quarters.
d + q = 250
Subtract 'q' to both sides:
d = -q + 250
Plug in '-q + 250' for 'd' in the 1st equation:
0.10(-q + 250) + 0.25q = 39.25
Distribute 0.10:
-0.10q + 25 + 0.25q = 39.25
Combine like terms:
0.15q + 25 = 39.25
Subtract 25 to both sides:
0.15q = 14.25
Divide 0.15 to both sides:
q = 95
Now plug this into any of the two equations to find 'd':
d + q = 250
d + 95 = 250
Subtract 95 to both sides:
d = 155
So there are 95 quarters and 155 dimes.
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Answer:
A- 15-5 is the same
Step-by-step explanation:
15 + (3-8)
15 + (-5)
15-5
X+(x+1)+(x+2)+(x+3)=156
4x+6=156
4x=150
x=37.5 (not an integer)
If x=37 you get 37+38+39+40=154 and if x=38 you get 38+39+40+41=158[/tex]
