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3 years ago

What is the probability of choosing a square

1 answer:

4 0

Answer:

I hope this answers your questions.

Explanation:

Divide the number of events by the number of possible outcomes. This will give us the probability of a single event occurring.

I hope this helps!!!!

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I need help on this one pls help me

vekshin1

What is the question?

6 0

3 years ago

Read 2 more answers

A square is inscribed In a circle with radius 6<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2%7D%20" id="TexFormula1" title="

34kurt

Answer:

48 in

Step-by-step explanation:

The diagonal of the inscribed square equals the diameter of the circle.

1. Calculate the diagonal of the square

d = 2r = 2 × 6√2 in =12√2 in

2. Calculate the side of the square

∆ACB is an isosceles right triangle.

We can use Pythagoras' Theorem to calculate the length of a side s.

$\begin{array}{rcl}s^{2} + s^{2} & = & (12\sqrt{2})^{2}\\2s^{2} & = & 144 \times 2\\s^{2} & = & 144\\s & = & \text{12 in}\\\end{array}$

3. Calculate the perimeter of the square

P = 4s = 4 × 12 in = 48 in

The perimeter of the square is 48 in.

6 0

3 years ago

Rebbeca's recipe calls for 4/5 of a cup of flour. She plans to make 1/4 of the recipe. How much flour will she use?

sukhopar [10]

1/4 of 4/5
=16/20 divided by 5/20
=16/20*20/5
=320/100
=3.2 or 3 1/5

3 0

3 years ago

Read 2 more answers

Lola's hockey team lost 15% of

MAVERICK [17]

Answer:

$20$

Step-by-step explanation:

Let $x$ = games played in total

From the fact that $15\%$ of the games the team played is equivalent to $3$ games, we can write:

$15\%x = 3$

$x=3\div 15\%$

$=20$

∴ Lola's hockey team played a total of 20 games.

Hope this helps :)

3 0

3 years ago

HELPPPPP ME GUYSSSS........

tamaranim1 [39]

Answer:

$\rm\displaystyle (x + 2{)}^{2} + (y + 5 {)}^{2} = {1}^{}$

$\rm\displaystyle (x - 7{)}^{2} + (y + 3{)}^{2} = { 7 }$

Step-by-step explanation:

<h3>QUESTION-1:</h3>

we are given the center and the redious of a circle equation

remember that,

$\rm\displaystyle E _{c} :(x - h {)}^{2} + (y - k {)}^{2} = {r}^{2}$

where (h,k) is the centre coordinate and r is redious of the circle

given that, h=-2 , k=-5 and r=1

Thus substitute:

$\rm\displaystyle (x - ( - 2){)}^{2} + (y - ( - 5) {)}^{2} = {1}^{2}$

simplify:

$\rm\displaystyle (x + 2{)}^{2} + (y + 5 {)}^{2} = {1}^{}$

<h3>QUESTION-2:</h3>

Likewise

$\rm\displaystyle E _{c} :(x - h {)}^{2} + (y - k {)}^{2} = {r}^{2}$

given that,h=7,k=-3 and r=√7

substitute:

$\rm\displaystyle (x - (7{))}^{2} + (y - ( - 3){)}^{2} = { \sqrt{7} ^{2} }$

simplify:

$\rm\displaystyle (x - 7{)}^{2} + (y + 3{)}^{2} = { 7 }$

5 0

2 years ago