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Leno4ka [110]
3 years ago
7

What is the probability of choosing a square

Mathematics
1 answer:
Ghella [55]3 years ago
4 0
Answer:

I hope this answers your questions.


Explanation:

Divide the number of events by the number of possible outcomes. This will give us the probability of a single event occurring.

I hope this helps!!!!
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I need help on this one pls help me
vekshin1
What is the question?
6 0
3 years ago
Read 2 more answers
A square is inscribed In a circle with radius 6<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2%7D%20" id="TexFormula1" title="
34kurt

Answer:

48 in

Step-by-step explanation:

The diagonal of the inscribed square equals the diameter of the circle.

1. Calculate the diagonal of the square

d = 2r = 2 × 6√2 in =12√2 in

2. Calculate the side of the square

∆ACB is an isosceles right triangle.

We can use Pythagoras' Theorem to calculate the length of a side s.

\begin{array}{rcl}s^{2} + s^{2} & = & (12\sqrt{2})^{2}\\2s^{2} & = & 144 \times 2\\s^{2} & = & 144\\s & = & \text{12 in}\\\end{array}

3. Calculate the perimeter of the square

P = 4s = 4 × 12 in = 48 in

The perimeter of the square is 48 in.

6 0
3 years ago
Rebbeca's recipe calls for 4/5 of a cup of flour. She plans to make 1/4 of the recipe. How much flour will she use?
sukhopar [10]
1/4 of 4/5
=16/20 divided by 5/20
=16/20*20/5
=320/100
=3.2 or 3 1/5
3 0
3 years ago
Read 2 more answers
Lola's hockey team lost 15% of
MAVERICK [17]

Answer:

20

Step-by-step explanation:

Let x = games played in total

From the fact that 15\% of the games the team played is equivalent to 3 games, we can write:

15\%x = 3

x=3\div 15\%

=20

∴ Lola's hockey team played a total of 20 games.

Hope this helps :)

3 0
3 years ago
HELPPPPP ME GUYSSSS........
tamaranim1 [39]

Answer:

\rm\displaystyle (x  +  2{)}^{2}  + (y  + 5 {)}^{2}  =  {1}^{}

\rm\displaystyle (x - 7{)}^{2}  + (y  + 3{)}^{2}  =  { 7 }

Step-by-step explanation:

<h3>QUESTION-1:</h3>

we are given the center and the redious of a circle equation

remember that,

\rm\displaystyle E _{c} :(x - h {)}^{2}  + (y - k {)}^{2}  =  {r}^{2}

where (h,k) is the centre coordinate and r is redious of the circle

given that, h=-2 , k=-5 and r=1

Thus substitute:

\rm\displaystyle (x - ( - 2){)}^{2}  + (y - ( - 5) {)}^{2}  =  {1}^{2}

simplify:

\rm\displaystyle (x  +  2{)}^{2}  + (y  + 5 {)}^{2}  =  {1}^{}

<h3>QUESTION-2:</h3>

Likewise

\rm\displaystyle E _{c} :(x - h {)}^{2}  + (y - k {)}^{2}  =  {r}^{2}

given that,h=7,k=-3 and r=√7

substitute:

\rm\displaystyle (x - (7{))}^{2}  + (y - ( - 3){)}^{2}  =  { \sqrt{7}  ^{2}   }

simplify:

\rm\displaystyle (x - 7{)}^{2}  + (y  + 3{)}^{2}  =  { 7 }

5 0
2 years ago
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