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Tom [10]
3 years ago
14

What is 207,968÷97 equal to.

Mathematics
2 answers:
lisov135 [29]3 years ago
4 0

Answer2144


Step-by-step explanation:


finlep [7]3 years ago
3 0

Answer:

2144

Step-by-step explanation:


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Can someone please help and explain
dangina [55]

Answer:

c = 300000 {(1.05)}^{50}

Step-by-step explanation:

The future value formula is FV=PV(1+i)^n, where the present value PV increases for each period into the future by a factor of 1 + i.  value PV increases for each period into the future by a factor of 1 + i. 

fv = pv {(1 + r)}^{n}

fv = future value

pv = present value

r = annual interest rate ( decimal number)

n= period

7 0
3 years ago
Find the diameter of a circle with an area of 6767 square centimeters.
scZoUnD [109]
  • Area=6767cm²

Diameter be d

Radius be r

  • πr²=6767
  • r²=6767/π
  • r²=2155
  • r=46.4cm

Diameter=2r=46.4(2)=92.8cm

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2 years ago
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How much will you pay back a bank in total for a $100,000 loan at 5% interest?
crimeas [40]

150000 cash buddy boi

7 0
4 years ago
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Simplify (x^5/x^2)^2 . Explain your steps.
Contact [7]

Answer:

x^6

Step-by-step explanation:

\left(\frac{x^5}{x^2}\right)^2

\frac{\left(x^5\right)^2}{\left(x^2\right)^2}

\frac{x^{10}}{x^4}

x^{10-4}

x^6

7 0
4 years ago
Find the zeros of y = x2 – 6x – 4 by completing the square.
katrin [286]

Answer:

The solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

Step-by-step explanation:

Given the function

y\:=\:x^2\:-\:6x\:-\:4

substitute y = 0 in the equation to determine the zeros

0\:=\:x^2\:-\:6x\:-\:4

Switch sides

x^2-6x-4=0

Add 4 to both sides

x^2-6x-4+4=0+4

Simplify

x^2-6x=4

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2

x^2-6x+\left(-3\right)^2=13

Apply perfect square formula:  (a-b)² = a²-2ab+b²

\left(x-3\right)^2=13

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-3=\sqrt{13}

Add 3 to both sides

x-3+3=\sqrt{13}+3

Simplify

x=\sqrt{13}+3

now solving

x-3=-\sqrt{13}

Add 3 to both sides

x-3+3=-\sqrt{13}+3

Simplify

x=-\sqrt{13}+3

Thus, the solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

4 0
3 years ago
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