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2 years ago

8

3/200 as a decimal and a percent helppp again please

1 answer:

icang [17]2 years ago

7 0

The answer is .015

Hope this helps

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The length of a rectangle is 10cm longer than its breadth the perimeter is 48cm determine the area of the rectangle

damaskus [11]

Answer:

djdjkffk Friesland whether

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2 years ago

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Megan consumed 3.5 gallons of water in one day. How many milliliters are equal to 3.5 gallons, if 1 liter = 1,000 milliliters an

Morgarella [4.7K]

B, 13,247.5 milliliters

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3 years ago

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The highest scorer of the women's basketball championship was Jessica Bradley. She scored 114 more points than Tina Harner, her

Harman [31]

THIS IS AN EXAMPLE:

Answer: Bradley scored 854 points and Harner scored 748 points.

Step-by-step explanation:

Start by representing the problem mathematically. "B" will represent Bradley's score, and "H" will represent Harner's score.

B+H=1602 represents that the sum of the scores is 1602.

B-H=106 represents that Bradley has 106 more points than Harner.

Now, combine the like terms in the two equations to get 2B=1708 . Now divide each side by two to find that Bradley scored 854 points.

Now, we can just subtract Bradley's score from the total score to get Harner's score. 1602-854=748, so Harner scored 748 points.

8 0

3 years ago

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Find the solution of the given initial value problem in explicit form. y′=(1−5x)y2, y(0)=−12 Enclose numerators and denominators

Nata [24]

Answer:

The solution is $y=-\frac{12}{12x-30x^2+1}$ .

Step-by-step explanation:

A first order differential equation $y'=f(x,y)$ is called a separable equation if the function $f(x,y)$ can be factored into the product of two functions of $x$ and $y$ :

$f(x,y)=p(x)h(y)$

where $p(x)$ and $h(y)$ are continuous functions.

We have the following differential equation

$y'=(1-5x)y^2, \quad y(0)=-12$

In the given case $p(x)=1-5x$ and $h(y)=y^2$ .

We divide the equation by $h(y)$ and move $dx$ to the right side:

$\frac{1}{y^2}dy\:=(1-5x)dx$

Next, integrate both sides:

$\int \frac{1}{y^2}dy\:=\int(1-5x)dx\\\\-\frac{1}{y}=x-\frac{5x^2}{2}+C$

Now, we solve for $y$

$-\frac{1}{y}=x-\frac{5x^2}{2}+C\\-\frac{1}{y}\cdot \:2y=x\cdot \:2y-\frac{5x^2}{2}\cdot \:2y+C\cdot \:2y\\-2=2yx-5yx^2+2Cy\\y\left(2x-5x^2+2C\right)=-2\\\\y=-\frac{2}{2x-5x^2+2C}$

We use the initial condition $y(0)=-12$ to find the value of C.

$-12=-\frac{2}{2\left(0\right)-5\left(0\right)^2+2C}\\-12=-\frac{1}{c}\\c=\frac{1}{12}$

Therefore,

$y=-\frac{2}{2x-5x^2+2(\frac{1}{12})}\\y=-\frac{12}{12x-30x^2+1}$

4 0

3 years ago

in sports club there are 800 members . the ratio of soccer members to social members is 5to 3 how many soccer players are there

attashe74 [19]

5:3

5+3=8
8 units

800=8 units
divide oth sides by 8
100=1 units

soccer=5 units=5 times 100=500
social=3 units=3 times 100=300

500 soccer players

5 0

2 years ago