Answer:
No solution
Step-by-step explanation:
Answer:
Henri invested $ 4,500 in bonds and $ 19,500 in stocks.
Step-by-step explanation:
Given that Henri has $ 24000 invested in stocks and bonds, and the amount in stocks is $ 6000 more than three times the amount in bonds, to determine the amount that Henri invested in stocks (S) and the amount he invested in bonds (B), the following calculations must be performed:
6000 + 3B + B = 24000
3B + B = 24000 - 6000
4B = 18000
B = 18000/4
B = 4500
S = 6000 + 3x4500
S = 6000 + 13500
S = 19500
Thus, Henri invested $ 4,500 in bonds and $ 19,500 in stocks.
A. 36 square units
(Please tell me if I’m right in the comments)
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Answer:
-5
Step-by-step explanation:
Answer:
1.6 < x < 9.6
Step-by-step explanation:
The smallest the third side can be is greater than the difference of the other two sides
x > 5.6 -4
x > 1.6
The largest the third side can be is less than the sum of the other two sides
x < 5.6 +4
x < 9.6
1.6 < x < 9.6