Answer:
The sample size needed is 2401.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error of the interval is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.
We have to find n, for which M = 0.02.
There is no estimate of p available, so we use 






The sample size needed is 2401.
hmmm units rates are just a matter of one above the other.
in this case is points/week.
9/15 points/weeks, we can just divide 9 ÷ 15 = 0.6, or 3/5.
so 0.6 points/weeks.
Answer:
option 2 or y + x -2 = 0
Step-by-step explanation:
Given a line on a graph, it is easiest to start with point-slope form.
y = mx + b
where m is the slope (rise/run) and b is the y-axis intercept.
From the plot m = -2/2 = -1 and b = 2 SO
y = mx + b
y = -x + 2
Then the general form is
y + x -2 = 0