The probability that a data value is between 54 and 66 is 81.9%
z score is used to determine by how many standard deviations the raw score is above or below the mean.
The z score is given by:
Given that μ = 62, σ = 4
For x = 54:
For x = 66:
P(54 < x < 66) = P(-2 < z < 1) = P(z < 1) - P(z < -2) = 0.8413 - 0.0228 = 81.9%
The probability that a data value is between 54 and 66 is 81.9%
Find out more on z score at: brainly.com/question/25638875
Answer:
The letter "b" indicates it is effective against flammable liquid fires.
Step-by-step explanation:
The letters on fire extinguishers represents the class of fire for which they can be used.
The letter "b" here indicate the b-1 extinguisher is effective against flammable liquid fires. These can be fires where cooking liquid , oil , gasoline , kerosene or paint.
Answer:
![\sqrt[4] {x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%20%7Bx%5E3%7D)
Step-by-step explanation:
At this point, we can transform the square root into a fourth root by squaring the argument, and bring into the other root:
![\sqrt x \cdot \sqrt[4] x =\sqrt [4] {x^2} \cdot \sqrt[4] x = \sqrt[4]{x^2\cdot x} = \sqrt[4] {x^3}](https://tex.z-dn.net/?f=%5Csqrt%20x%20%5Ccdot%20%5Csqrt%5B4%5D%20x%20%3D%5Csqrt%20%5B4%5D%20%7Bx%5E2%7D%20%5Ccdot%20%5Csqrt%5B4%5D%20x%20%3D%20%5Csqrt%5B4%5D%7Bx%5E2%5Ccdot%20x%7D%20%3D%20%5Csqrt%5B4%5D%20%7Bx%5E3%7D)
Alternatively, if you're allowed to use rational exponents, we can convert everything:
![\sqrt x \cdot \sqrt[4] x = x^{\frac12} \cdot x^\frac14 = x^{\frac12 +\frac14}= x^{\frac24 +\frac14}= x^\frac34 = \sqrt[4] {x^3}](https://tex.z-dn.net/?f=%5Csqrt%20x%20%5Ccdot%20%5Csqrt%5B4%5D%20x%20%3D%20x%5E%7B%5Cfrac12%7D%20%5Ccdot%20x%5E%5Cfrac14%20%3D%20x%5E%7B%5Cfrac12%20%2B%5Cfrac14%7D%3D%20x%5E%7B%5Cfrac24%20%2B%5Cfrac14%7D%3D%20x%5E%5Cfrac34%20%3D%20%5Csqrt%5B4%5D%20%7Bx%5E3%7D)
Answer:
Hey mate.....
Step-by-step explanation:
This is ur answer.....
<h2>D. 3c + 2b</h2>
Hope it helps!
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The answer is R=0.053707443....
Round to the nearest decimal place as it asks for
i hope this helps :)
