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3 years ago

What does not contain an irrational number?

Mathematics

2 answers:

Aleksandr-060686 [28]3 years ago

6 0

Answer:

i think it's the first option.

spayn [35]3 years ago

4 0

Answer:

A. ( well... The first option)

Step-by-step explanation:

Any number that can be written as a fraction with integers is called a rational number. Which the numbers on option one is a perfect example of a rational number instead of a irrational number.

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Inessa05 [86]

Answer:

Side AB has a length of 4, and side BC has a length of 11.7

7 0

3 years ago

ANSWER NEEDED QUICK! Divide: 5/8 divided by 3/4 1/8 5/6 3/4 1 1/2

Scilla [17]

5/6 I think tahts the answer hope this helps

8 0

3 years ago

Can some kind person help me with this it will really mean a a lot

nasty-shy [4]

Answer:

Table B

Table C

Table A

Step-by-step explanation:

Substitute by the easiest number which is 0

f(0) =2(0) - (-3) =3 Then it is Table B function

f(0) = -2(0) +(-1/3)= -1/3 Then it is Table C function

f(0) =2(0) +(2/3)=2/3 Then it is Table A function

6 0

2 years ago

Marcus was training for a 2,000 meter race. He had to alternate between running and walking.

evablogger [386]

Answer:

if marcus ran 1,600 meters that means he walked 400 meters

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Katrina buys a 42-ft roll of fencing to make a rectangular play area for her dogs.

vekshin1

Answer:

(a) $l = -w + 21$

(b) Domain: $0$ (See attachment for graph)

Step-by-step explanation:

Given

$2(l + w) = 42$

$l = length$

$w = width$

Solving (a): A function; l in terms of w

All we need to do is make l the subject in $2(l + w) = 42$

Divide through by 2

$l + w = 21$

Subtract w from both sides

$l + w - w = 21 - w$

$l = 21 - w$

Reorder

$l = -w + 21$

Solving (b): The graph

In (a), we have:

$l = -w + 21$

Since l and w are the dimensions of the fence, they can't be less than 1

So, the domain of the function can be $0$

--------------------------------------------------------------------------------------------------

To check this

When $w = 1$

$l = -1 + 21$

$l = 20$

$(w,l) = (1,20)$

When $w = 20$

$l = -20 + 21$

$l = 1$

$(w,l)= (20,1)$

--------------------------------------------------------------------------------------------------

See attachment for graph

Solving (c): Write l as a function $f(w)$

In (a), we have:

$l = -w + 21$

Writing l as a function, we have:

$l = f(w)$

Substitute $f(w)$ for l in $l = -w + 21$

$l = -w + 21$ becomes

$f(w) = -w + 21$

5 0

3 years ago