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sesenic [268]
3 years ago
13

If the sum of 28% is 100.8, what is the sum

Mathematics
2 answers:
Nadusha1986 [10]3 years ago
8 0
Cross multiple:


28%/100% = 100.8/x


28x = 10,080


X=$360.00
zzz [600]3 years ago
7 0
$360. Divide 100.8 by .28

You can check your answer by multiplying .28 by 100.8
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Simplify the radical expression. Leave it in radical form. SHOW YOUR WORK<br><br> √75 + √3 √75 + √3
gayaneshka [121]
15+6<span>√3 is the correct answer.

Work:  
</span><span>√75 + √3 √75 + √3
5</span>√3+√3+√3*5√3
6√3+3*5
15+6√3
6 0
3 years ago
An insured's roof cost $4,000 when installed 5 years ago. It has been damaged by hail and must be replaced. The new roof will co
hoa [83]

Answer:

ACV=$4,500

Step-by-step explanation:

We have that the actual cash value (ACV) is defined as:

ACV=\dfrac{R\times(E-C)}{E}

Where:

ACV = actual cash value

R = replacement cost or purchase price of the item

E = expected life of the item

C = current life of the item

Then we have R=$6,000, C=5years, and to find the expected life of the item we can use the depreciating of the roof, then if the roof is depreciating $200 each year we just need to divide $4,000 by $200 to find the expected life of the roof:

\dfrac{4,000}{200}=20

Then the espected life of the roof is 20 years, with this result we have all the data, then:

ACV=\dfrac{\$6,000\times (20-5)}{20}=\dfrac{\$6,000\times (15)}{20}=\dfrac{\$90,000}{20}=\$4,500

Then the ACV is $4,500

5 0
3 years ago
* Identify the first 6 multiples of 10​
bezimeni [28]

Answer:

10, 20, 30, 40, 50, 60

Step-by-step explanation:

you just have to list the multiples

pls vote brainliest if this helped

8 0
3 years ago
Read 2 more answers
A circle has a circumference of 42 in.what is the area of the circle
Solnce55 [7]

Answer:

140.37 in²

Step-by-step explanation:

C = 2πr

42 = 2πr

21 = πr

r = 21/π

A = πr²

A = π × (21/π)²

≈ 140.37 in²

3 0
3 years ago
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zmey [24]

Answer: 120[4(x^6 + x^3 + x^4 + x) +7(x^7 + x^4 + x^5 + x^2)]

Step-by-step explanation:

=24x(x^2 + 1)4(x^3 + 1)5 + 42x^2(x^2 + 1)5(x^3 + 1)4

Remove the brackets first

=[(24x^3 +24x)(4x^3 + 4)]5 + [(42x^4 +42x^2)(5x^3 + 5)4]

=[(96x^6 + 96x^3 +96x^4 + 96x)5] + [(210x^7 + 210x^4 + 210x^5 + 210x^2)4]

=(480x^6 + 480x^3 + 480x^4 + 480x) + (840x^7 + 840x^4 + 840x^5 + 840x^2)

Then the common:

=[480(x^6 + x^3 + x^4 + x) + 840(x^7 + x^4 + x^5 + x^2)]

=120[4(x^6 + x^3 + x^4 + x) +7(x^7 + x^4 + x^5 + x^2)]

6 0
3 years ago
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