Answer:
UV=142
Step-by-step explanation:
21x-13=10x+31
+13 +13
21x=10x+44
-10x=-10x
11x=44
÷11 ÷11
x=4
now substitute 4 in place of x (only have to solve one)
21(4)-13= 71
now multiply your answer by 2
71×2=142
1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
#3.
√18²-5.7² Second Choice
#4
l²=5²+4² = 25+16 = = 41
l=√41
l= 6.4
Second Choice
#5 Only A --- First choice
#7 6 ----- Third choice
#8 V=

942 units³ ---Second choice
It takes 1.5 hours for 4 workers to paint the same room
<em><u>Solution:</u></em>
Given that 3 workers can paint a room in 2 hours
To find: Time taken for 4 workers to paint the same room
Assume the time needed to paint the room is inversely proportional to the number of worker

Where, "k" is the constant of proportionality
<em><u>3 workers can paint a room in 2 hours</u></em>
Substitute number of workers = 3 and time = 2 hours

Therefore,

To find time taken for 4 workers to paint the same room, substitute number of workers = 4 in above expression

Thus it takes 1.5 hours for 4 workers to paint the same room
72 1/9
0.1 recurring of the number 1 is 1/9 of the number