Question

Given two vectors a⃗ =4.00i^+7.00j^ and b⃗ =5.00i^−2.00j^ , find the vector product a⃗ ×b⃗ (expressed in unit vectors). what is the magnitude

Answer 1

The vector product of $\boxed{a \times b = - 43\hat k}$ and the magnitude of $a \times b$ is $\boxed{43}.$

Further explanation:

Given:

Vector a is $\vec a = 4.00\hat i + 7.00\hat j.$

Vector b is $\vec b = 5.00\hat i - 2.00\hat j.$

Explanation:

The cross product of a \times b can be obtained as follows,

$\begin{aligned}a \times b &= \left| {\begin{array}{*{20}{c}}{\hat i}&{\hat j}&{\hat k} \\4&7&0\\5&{ - 2}&0 \end{array}}\right|\\&= \hat i\left( {0 - 0} \right) - \hat j\left( {0 - 0} \right) + \hat k\left( { - 9 - 35} \right)\\&= 0\hat i - 0\hat j - 43\hat k\\&= - 43\hat k\\\end{aligned}$

The vector can be expressed as follows,

$a \times b = - 43\hat k$

The magnitude of $a \times b$can be obtained as follows,

$\begin{aligned}\left| {a \times b} \right| &= \sqrt {{0^2} + {0^2} + {{\left( { - 43} \right)}^2}}\\&= \sqrt {{{43}^2}}\\&= 43\\\end{aligned}$43404

The vector product of $\boxed{a \times b = - 43\hat k}$ and the magnitude of $a \times b$ is $\boxed{43}.$

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Answer details:

Grade: High School

Subject: Mathematics

Chapter: Vectors

Keywords: two vectors, vector product, expressed in unit vectors, magnitude, vector a, vector b, a=4.00i^+7.00j^, b=5.00i^-2.00j^, unit vectors, vector space.

Answer 2

We have the following vectors:
 a = 4.00i + 7.00j
 b = 5.00i-2.00j
 We make the vector product:
 a x b = (4 * (- 2)) k - (7 * 5) k = -8k -35k = -43k
 The magnitude of the vector is:
 la x bl = root ((- 43) ^ 2) = 43
 Answer:
 the vector product is:
 -43k
 the magnitude is:
 43