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4vir4ik [10]
3 years ago
9

Vega wants to prove that the segment joining midpoints of two sides of a triangle is half the length of the third side. Select t

he appropriate rephrased statement for Vega's proof.
Here are the answer choices:

Mathematics
1 answer:
konstantin123 [22]3 years ago
7 0

Answer:

The Answer is D : In triangle EFG△ , if EH=HF and EI=IG , then HI= 1/2 FG

​

FGH, I, equals, start fraction, 1, divided by, 2, end fraction, F, G.

Step-by-step explanation:

I Saw on Khan Academy

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1/8 if they are numbered 1-8
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andre [41]

Answer:

150

Step-by-step explanation:

Knowing that a cube has 6 faces which all are equal.

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Since, it given that one face is 5 cm

Then, we also must know the formula for area of a cube

Which is:

Area=6a^2

Thus,

Area=6a^2

Area=6(5)^2

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Area=150

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2 years ago
Determine if true:<br> 9x0^1x9=9
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Answer:

False

Step-by-step explanation:

9x0=0

0^1=0

0x9=0

0=9

The numbers don't match.

Hence, the equation is false.

5 0
2 years ago
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Clara has a purse in the shape of a trapezoid.The top of the purse measures 22 cm while the bottom of the purse measures 36 cm.
Blababa [14]

Answer:

38

Step-by-step explanation:

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Here is a triangular pyramid and its net.
galben [10]

Answer:

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. \text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\

{\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\  mm^{2}

Hence,

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

8 0
3 years ago
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