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Dahasolnce [82]
3 years ago
5

PLEASE HELP!

Mathematics
1 answer:
photoshop1234 [79]3 years ago
3 0
To find the percent change between two numbers (based off of 434.90, or the first number listed), we first find the difference between the two numbers. To do this, we subtract the first number from the second. Here, we have 573.90-434.90=139.  Then, we divide the difference by the original number, resulting in \frac{139}{434.9} =0.3196137043. Finally, we multiply that answer by 100 to turn it into a percentage, resulting in 31.96137043 as our percentage. This is a positive increase because our number is positive.

Feel free to ask further questions!
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If the inspection division of a county weights and measures department wants to estimate the mean amount of
Amanda [17]

If inspection department wants to estimate the mean amount with 95% confidence level with standard deviation 0.05 then it needed a sample size of 97.

Given 95% confidence level, standard deviation=0.05.

We know that margin of error is the range of values below and above the sample statistic in a confidence interval.

We assume that the values follow normal distribution. Normal distribution is a probability that is symmetric about the mean showing the data  near the mean are more frequent in occurence than data far from mean.

We know that margin of error for a confidence interval is given by:

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Solving for n using formula of margin of error.

n=(z/2ST/Me)^{2}

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Hence the sample size required will be 97.

Learn more about standard deviation at brainly.com/question/475676

#SPJ4

The given question is incomplete and the full question is as under:

If the inspection division of a county weights and measures department wants to estimate the mean amount of soft drink fill in 2 liters bottles to within (0.01 liter with 95% confidence and also assumes that standard deviation is 0.05 liter. What is the sample size needed?

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